Question

如何将以下内容插入neo4j

create (st:serviceticket {name:'SRT_519'}) 
with st as st 
match (st:serviceticket) where st.name='SRT_519' 
match (d:ProductID) where d.name ='PRD_1014'
with st as st , d as d 
merge (d)-[:SERVICE_TICKETID]->(st);


create (st:serviceticket {name:'SRT_520'}) 
with st as st 
match (st:serviceticket) where st.name='SRT_520'
match (d:ProductID) where d.name ='PRD_1004'
with st as st , d as d 
merge (d)-[:SERVICE_TICKETID]->(st);

如果我有多个这样的记录插入如何插入所有这些记录。请帮助我。

Answer 1

我假设您的产品的节点已经存在。

请记住，您的“st”是一个引用，并且您尝试在一个批次中分配两次相同的引用。第一步是为您的服务票单提供单独的参考

match (d:ProductID), (e:ProductID)
where d.name ='PRD_1014'and
e.name ='PRD_1004'
create (st519:serviceticket {name:'SRT_519'}) 
create (st520:serviceticket {name:'SRT_520'}) 


merge (d)-[:SERVICE_TICKETID]->(st519)
merge (e)-[:SERVICE_TICKETID]->(st520)

Answer 2

如果使用参数，则可以提供一组对：

你应该有一个索引或约束：ServiceTicket（name）和：ProductID（name）

WITH [['SRT_519','PRD_1014']] as data
FOREACH (pair in data |
    MERGE (st:ServiceTicket {name:data[0]}),(d:ProductID {name:data[1]})
    MERGE (d)-[:SERVICE_TICKETID]->(st);
)

neo4j使用cypher批量插入

2 个答案: