Question

我有这个简单的程序来存储和检索数据库中的文件，我可以运行文件的插入，但我似乎无法运行代码冷却检索文件。

我正在使用MSSQL作为我的数据库

以下是测试连接的代码（process1.php）：

<?php

class Connection {

    public $conn;

    public function connectDatabase() {
        $serverName = "localhost"; 
        $uid = "sa";   
        $pwd = "joseph04";  
        $databaseName = "Profile"; 

        $connectionInfo = array( "UID"=>$uid, "PWD"=>$pwd, "Database"=>$databaseName); 

        // Connect using SQL Server Authentication 


        $this->conn = sqlsrv_connect( $serverName, $connectionInfo);  

        // Test Connection
        if( $this->conn === false )
        {
            echo "Connection could not be established.\n";
            die( print_r( sqlsrv_errors(), true));
        }
    }
}

?>

这是用于在数据库中检索数据的代码（ShowProcess.php）：

<?php

include_once("process1.php");

class showData extends Connection {
  public function doShowData(){
    //declare the SQL statement that will query the database
         $query = "SELECT col1, col2 ";
         $query .= "FROM dbo.ProfileTable ";

    //execute the SQL query and return records
         $result = sqlsrv_query($this->conn, $query)
             or die( print_r( sqlsrv_errors(), true));

    //Show results in table

    $o = '<table id="myTable">
            <thead>
            <tr>
            <th>Col 1</th>
            <th>Col 2</th>
            </tr>
            </thead><tbody>';

          while ( $record = sqlsrv_fetch_array($result) )
              {
                  $o .= '<tr><td>'.$record ['col1'].'</td><td>'.$record ['col2'].'</td></tr>';
              }               

          $o .= '</tbody></table>';

          echo $o;



        //Show result from sql table separated by comma (commented out)
           /* while ( $record = mssql_fetch_array($result) )
            {
                echo $record["col1"] . " , " . $record["col2"] . "<br />";
            } */

        //free result set memory
            sqlsrv_free_stmt($result);

        //close the connection
            sqlsrv_close($this->conn);
  }
}

if (isset($_POST['formView'])){ 
  $i = new showData;
  $i->connectDatabase();
  $i->doShowData();
}

?>

这是我的错误代码：

Array ( [0] => Array ( [0] => 42S22 [SQLSTATE] => 42S22 [1] => 207 [code] => 207 [2] => [Microsoft][SQL Server Native Client 11.0][SQL Server]Invalid column name 'col1'. [message] => [Microsoft][SQL Server Native Client 11.0][SQL Server]Invalid column name 'col1'. ) [1] => Array ( [0] => 42S22 [SQLSTATE] => 42S22 [1] => 207 [code] => 207 [2] => [Microsoft][SQL Server Native Client 11.0][SQL Server]Invalid column name 'col2'. [message] => [Microsoft][SQL Server Native Client 11.0][SQL Server]Invalid column name 'col2'. ) )

我想我已经搞砸了sqlsrv_query()参数

请帮帮忙？我只是PHP和MSSQL的新手。谢谢！

如果我使用你的代码，我也会从@klcant中获取代码。谢谢！

Answer 1

@Abhishek这里是输出：

好的，我已经做到了，这就是输出：

数组（[0] =＆gt; [名称] =＆gt; [1] =＆gt; 0 [年龄] =＆gt; 0 [2] =＆gt; [性别] =＆gt;）数组（[0] = ＆gt; Cayas [名称] =＆gt; Cayas [1] =＆gt; 35 [年龄] =＆gt; 35 [2] =＆gt;女性[性别] =＆gt;女性）数组（[0] =＆gt; Celina [名称] ] =＆gt; Celina [1] =＆gt; 19 [年龄] =＆gt; 19 [2] =＆gt;女性[性别] =＆gt;女性）数组（[0] =＆gt; Chala [名称] =＆gt; Chala [1] =＆gt; 90 [年龄] =＆gt; 90 [2] =＆gt;女性[性别] =＆gt;女性）数组（[0] =＆gt; Inna [名称] =＆gt; Inna [1] =＆gt ; 19 [年龄] =＆gt; 19 [2] =＆gt;女性[性别] =＆gt;女性）数组（[0] =＆gt; Jenina [姓名] =＆gt; Jenina [1] =＆gt; 19 [年龄] =＆gt; 19 [2] =＆gt;女性[性别] =＆gt;女性）数组（[0] =＆gt;约翰[姓名] =＆gt;约翰[1] =＆gt; 12 [年龄] =＆gt; 12 [ 2] =＆gt;男性[性别] =＆gt;男性）数组（[0] =＆gt;约瑟夫[姓名] =＆gt;约瑟夫[1] =＆gt; 19 [年龄] =＆gt; 19 [2] =＆gt;男性[性别] =＆gt;男性）数组（[0] =＆gt; Lady [姓名] =＆gt; Lady [1] =＆gt; 0 [年龄] =＆gt; 0 [2] =＆gt;女性[性别] = ＆gt;女性）数组（[0] =＆gt;玛丽[姓名] =＆gt;玛丽[1] =＆gt; 28 [年龄] =＆gt; 28 [2] =＆gt;女[性] =＆gt;女） Col 1 Col 2

Answer 2

好了，现在你使用这段代码，它可以解决你的问题 -

public function doShowData(){
    //declare the SQL statement that will query the database
         $query = "SELECT * ";
         $query .= "FROM dbo.ProfileTable ";
//execute the SQL query and return records
     $result = sqlsrv_query($this->conn, $query)
         or die( print_r( sqlsrv_errors(), true));

//Show results in table

$o = '<table id="myTable">
        <thead>
        <tr>
        <th>Name</th>
        <th>Age </th>
         <th>Sex</th>
        </tr>
        </thead><tbody>';

      while ( $record = sqlsrv_fetch_array($result) )
          {

              $o .= '<tr><td>'.$record ['Name'].'</td><td>'.$record ['Age'].'</td><td>'.$record ['Sex'].'</td></tr>';
          }               

      $o .= '</tbody></table>';

      echo $o;



    //Show result from sql table separated by comma (commented out)
       /* while ( $record = mssql_fetch_array($result) )
        {
            echo $record["col1"] . " , " . $record["col2"] . "<br />";
        } */

    //free result set memory
        sqlsrv_free_stmt($result);

    //close the connection
        sqlsrv_close($this->conn);


}

在从MSSQL数据库中检索数据时无法运行PHP代码

2 个答案: