Question

我在搜索最后一小时后如何实现这个问题时遇到了麻烦：

    if (age < 16)
    {
        System.out.println ("You can't drive " + name);
    }
    else if (age == 16-17)
    {
        System.out.println ("You can drive but you can't vote " + name);
    }
    else if (age == 18-24)
    {
        System.out.println ("You can vote but you can't rent a car " + name);
    }
    else
    {
        System.out.println ("You can do anything you wish " + name);
    }

我只是不确定如何使输入值等于一组或一组数字。我一直在研究最后一小时，我似乎无法找到一种简单的方法来实现一系列数字并将它们分配给if语句中的某些内容。这段代码实际上有效，但是如果任何int是＆gt; 16它默认为else语句。

Answer 1

现在您正在if age == (18 - 24)转换为age == -6。

如果您想检查范围，只需使用边界：if age >= 18 && age <= 24。

Answer 2

您的问题是您正在16-17，18-24进行数学减法。您应该使用age == 16 || age == 17和age >= 18 && age <= 24。就个人而言，我会尝试使用switch声明。

Answer 3

  if (age < 16)
    {
        System.out.println ("You can't drive " + name);
    }

    else if (age == 16 || age==17)
    {
        System.out.println ("You can drive but you can't vote " + name);
    }

    else if (age >=18 && age<=24)
    {
        System.out.println ("You can vote but you can't rent a car " + name);
    }

    else
    {
        System.out.println ("You can do anything you wish " + name);
    }

Answer 4

移动到函数

会更好

public static boolean isBetween(int x, int lower, int upper) {
  return x >= lower && x <= upper;
}

if (isBetween(age, 0, 15)) {
  System.out.println ("You can't drive " + name);
} 
if (isBetween(num, 16, 17)) {
  System.out.println ("You can drive but you can't vote " + name);
}

如何将int范围分配给if语句中的输入

4 个答案: