Question

我以前在这里看过这个问题，但没有一个解决方案适合我。我有一个带有Spring MVC的SmartGWT应用程序。这一切都很好，我有RESTful网络服务。

我有一个表单不仅可以上传文件，还可以上传一些元数据。有一个关联的DataSource具有以下形式：

private final String DEFAULT_FILE_UPLOAD_SERVICE_PATH = "upload";
private final String TARGET = "uploadTarget";

 public FileUploadForm()
{
    setEncoding(Encoding.MULTIPART);
    setMethod(FormMethod.POST);

    setAutoFetchData(false);
    setDataSource(fileUploadDS);

    setTitleOrientation(TitleOrientation.TOP);
    setNumCols(1);
    setColWidths("*");

    uploadFileIdItem.setRequired(true);
    uploadFileIdItem.setDefaultValue(0);
    uploadFileIdItem.setVisible(false);
    uploadFileIdItem.setShowTitle(false);

    // ==========================================================================

    fileUploadTypeSelectItem.setShowTitle(false);
    fileUploadTypeSelectItem.setName(Constants.FILE_UPLOAD_UPLOADTYPE);
    fileUploadTypeSelectItem.setPickListWidth(TEXT_SIZE);
    fileUploadTypeSelectItem.setTitle(Constants.TITLE_FILE_UPLOAD_UPLOADTYPE);
    fileUploadTypeSelectItem.setOptionDataSource(fileUploadTypeDS);
    fileUploadTypeSelectItem.setRequired(true);
    fileUploadTypeSelectItem.setDisplayField(Constants.FILE_UPLOAD_UPLOADTYPE_NAME);
    fileUploadTypeSelectItem.setValueField(Constants.FILE_UPLOAD_UPLOADTYPE_ID);
    fileUploadTypeSelectItem.setDataPath("fileUploadType/fileUploadTypeId");

    // ==========================================================================

    setAction(GWT.getHostPageBaseURL() + "rest/" + DEFAULT_FILE_UPLOAD_SERVICE_PATH);

    ButtonItem uploadButton = new ButtonItem("Upload");

    uploadButton.addClickHandler(new com.smartgwt.client.widgets.form.fields.events.ClickHandler()
    {
        @Override
        public void onClick(com.smartgwt.client.widgets.form.fields.events.ClickEvent event)
        {
            submitForm();
        }
    });

    FileItem uploadItem = new FileItem(Constants.FILENAME);
    uploadItem.setTitle(Constants.FILENAME);

    setFields(uploadFileIdItem, fileUploadTypeSelectItem, uploadItem, uploadButton);
}

所以，我不知道我是否需要使用： setAction（GWT.getHostPageBaseURL（）+＆＃34; rest /＆＃34; + DEFAULT_FILE_UPLOAD_SERVICE_PATH）; 要么 setAction（GWT.getHostPageBaseURL（）+ DEFAULT_FILE_UPLOAD_SERVICE_PATH）; 要么 setAction（GWT.getHostPageBaseURL（）+ DEFAULT_FILE_UPLOAD_SERVICE_PATH）;

这些似乎都不起作用，我提交数据以上传文件名，我不断收到HTTP 404错误。

我没有在serv.xml的web.xml文件中定义任何特别的东西。相反，springmvc-servlet包含：

<context:component-scan base-package="com.myself.products.app.server.controller" />

servlet实际上定义如下：

@SuppressWarnings("serial")
@Controller
@RequestMapping("/upload")
public class FileUploadServlet extends HttpServlet
{
    private final Logger logger = LoggerFactory.getLogger(FileUploadServlet.class);

    @Override
    public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
{
    this.process(request, response);
}

@Override
public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
{
    this.process(request, response);
}

private void process(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException
{
    // check that we have a file upload request
    if (ServletFileUpload.isMultipartContent(request))
    {
        processFiles(request, response);
    }
}

private File tmpDir;
private static final String DESTINATION_DIR_PATH = "/files/upload";
private File destinationDir;

public void init(ServletConfig config) throws ServletException
{
    super.init(config);

    tmpDir = new File(((File) getServletContext().getAttribute("javax.servlet.context.tempdir")).toString());

    if (!tmpDir.isDirectory())
    {
        throw new ServletException(tmpDir.toString() + " is not a directory");
    }

    logger.debug("tmpDir: " + tmpDir.toString());

    String realPath = getServletContext().getRealPath(DESTINATION_DIR_PATH);
    destinationDir = new File(realPath);

    if (!destinationDir.isDirectory())
    {
        throw new ServletException(DESTINATION_DIR_PATH + " is not a directory");
    }
}

private void processFiles(HttpServletRequest request, HttpServletResponse response) throws ServletException,
    IOException
{

    // create a factory for disk-based file items
    DiskFileItemFactory factory = new DiskFileItemFactory();

    // set the size threshold, above which content will be stored on disk
    factory.setSizeThreshold(1 * 1024 * 1024); // 1 MB

    // set the temporary directory (this is where files that exceed the threshold will be stored)
    factory.setRepository(tmpDir);

    // create a new file upload handler
    ServletFileUpload upload = new ServletFileUpload(factory);

    try
    {
        // parse the request
        List<?> items = upload.parseRequest(request);

        // process the uploaded items
        Iterator<?> itr = items.iterator();

        while (itr.hasNext())
        {
            FileItem item = (FileItem) itr.next();

            // write the uploaded file to the application's file staging area
            File file = new File(destinationDir, item.getName());
            item.write(file);
        }

    }
    catch (FileUploadException e)
    {
        logger.error("Error encountered while parsing the request", e);
    }
    catch (Exception e)
    {
        logger.error("Error encountered while uploading file", e);
    }
}

您之前在此网站和其他几个网站上看到过此代码。

如果可能，我想提交文件和数据，但如果没有，那么我该如何提交表单，然后提交元数据呢？

非常感谢任何帮助。

Answer 1

简单文件上传GWT示例：

可在此处获得： http://www.gwtproject.org/javadoc/latest/com/google/gwt/user/client/ui/FileUpload.html

要发送元数据和请求，需要将隐藏字段设置为面板：

import com.google.gwt.user.client.ui.Hidden;

Hidden hidden = new Hidden();
hidden.setName("json");
hidden.setVisible(false); 

hidden.setValue("simpleMetadata:testData");
panel.add(hidden);

Answer 2

我建议你单独保存元数据，从而使文件重叠，并有2个表单。这就是我正在做的事情，它对我有用：

uploadForm.setAction(GWT.getHostPageBaseURL() + "importServiceName");
uploadForm.setEncoding(Encoding.MULTIPART);
uploadForm.setTarget(TARGET);
uploadForm.setMethod(FormMethod.POST);
fileItem = new UploadItem("file");
fileItem.setTitle("File");
fileItem.setWidth(300);
NamedFrame frame = new NamedFrame(TARGET);
frame.setWidth("1");
frame.setHeight("1");
frame.setVisible(false);
uploadForm.setItems(fileItem);

我正在使用NamedFrame来获取gwt代码中的servlet响应，但这是另一回事。我在web.xml中手动定义servler

smartgwt spring servlet和上传文件

2 个答案: