Question

我正在为Symfony2项目中的API服务编写单元测试。一种服务方法将控制器实例作为参数，并处理请求的JSON。

    public function getJSONContent(Controller $controller) {
        $version = $this->getAPIVersion();

        //Read in request content
        $content = $controller->get("request")->getContent();
        if (empty($content)) {
            throw new HttpException(400, 'Empty request payload');
        }


        //Parse and Detect invalid JSON
        $jsonContent = json_decode($content, true);
        if($jsonContent === null) {
            throw new HttpException(400, 'Malformed JSON content received');
        }

        return $jsonContent;
    }

以下是我的测试：

class ApiTest extends \PHPUnit_Framework_TestCase {
    public function testGetJSONContent() {

        // Create a stub for the OrgController Object
        $stub = $this->getMock('OrganizationController');

        // Create the test JSON Content
        $post = 'Testy Test';
        $request = $post;
        $version = "VersionTest";
        $APIService = new APIService();

        // Configure the Stub to respond to the get and getContent methods
        $stub->expects($this->any())
             ->method('get')
             ->will($this->returnValue($post));

        $stub->expects($this->any())
             ->method('getContent')
             ->will($this->returnValue($request));

        $stub->expects($this->any())
             ->method('getAPIVersion')
             ->will($this->returnValue($version));


        $this->assertEquals('Testy Test', $APIService->getJSONContent($stub));
    }
}

我的测试引发以下错误：

传递给Main \ EntityBundle \ Service \ APIService :: getJSONContent（）的参数1必须是Symfony \ Bundle \ FrameworkBundle \ Controller \ Controller的实例，给出Mock_OrganizationController_767eac0e的实例。

我的存根显然不是在欺骗任何人，有什么方法可以解决这个问题吗？

Answer 1

使用命名空间指定要模拟的控制器。即。

    // Create a stub for the OrgController Object
    $stub = $this->getMock('Acme\AcmeBundle\Controller\OrganizationController');

Symfony2单元测试中的模拟控制器

1 个答案: