Question

我正在开发一个使用https://github.com/Gottox/socket.io-java-client实现socket io客户端的android应用程序。

我的Nodejs服务器

var app = require('http').createServer(),    
    io = require('socket.io').listen(app),
    http = require('http'),
    mysql = require('mysql'),
    connectionsArray = [],
    connection = mysql.createConnection({               
        host: 'localhost',
        user: 'root',
        password: '',
        database: 'login',
        port: 3306
    });

app.listen(3000);

io.sockets.on('connection', function (socket) { 
    socket.on('register_usernames', function (data) {
        io.sockets.socket(socket.id).emit('register_usernames' , {username:"one"});
        io.sockets.socket.(socket.id).emit('register_usernames_one', {username:"two"});
        getBookingHistory(data);
    });

    connectionsArray.push(socket);
});

Android客户端

package com.nuappz.socketdemo;

import io.socket.IOAcknowledge;
import io.socket.IOCallback;
import io.socket.SocketIO;
import io.socket.SocketIOException;

import java.net.MalformedURLException;

import org.json.JSONObject;

import android.app.Activity;
import android.os.Bundle;
import android.util.Log;

public class Search extends Activity implements IOCallback{
    SocketIO socket;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        // TODO Auto-generated method stub
        super.onCreate(savedInstanceState);
        try {
            // Try making the socket connection
            socket = new SocketIO("http://nuappzdev.weteksi.com:3000/");
            socket.connect(this);
        } catch (MalformedURLException e1) {
            // TODO Auto-generated catch block
            e1.printStackTrace();
        }

        socket.emit("register_usernames", "123");   
    }
    @Override
    public void onDisconnect() {
        // TODO Auto-generated method stub  
    }
    @Override
    public void onConnect() {
        // TODO Auto-generated method stub  
    }
    @Override
    public void onMessage(String data, IOAcknowledge ack) {
        // TODO Auto-generated method stub  
    }
    @Override
    public void onMessage(JSONObject json, IOAcknowledge ack) {
        // TODO Auto-generated method stub  
    }
    @Override
    public void on(String event, IOAcknowledge ack, Object... args) {
        // TODO Auto-generated method stub
        if(event.equals("register_usernames")) {
            Log.d("message response", args.toString());
        } else if (event.equals("register_usernames_one")) {
            Log.d("message reply", args.toString());
        }   
    }
    @Override
    public void onError(SocketIOException socketIOException) {
        // TODO Auto-generated method stub  
    }
}

在接收事件时的方法中，它显示args。但它显示以下错误

Logcat

06-09 18:25:52.321:I/io.socket(1890):>5:::{"args":       ["123"],"name":"register_usernames"}
06-09 18:25:52.322: I/io.socket(1890): < 1::
06-09 18:25:52.408: I/io.socket(1890): < 5:::{"name":"message_response","args":  [{"username":"one"}]}
06-09 18:25:52.409: D/message response(1890): [Ljava.lang.Object;@4177d208
06-09 18:25:52.409: I/io.socket(1890): < 5:::{"name":"message_reply","args": [{"username":"two"}]}
06-09 18:25:52.409: D/message reply(1890): [Ljava.lang.Object;@41739f30
06-09 18:25:52.471: D/dalvikvm(1890): threadid=16: interp stack at 0x5d914000

1.如何发送有关发射的数据以及如何从客户端获取数据 2.如何发送数组或Json并解析它。

Answer 1

我发现了真正的问题是什么因为我已经尝试在持有数组的对象中获取值对象本身就是一个数组。所以

我的尝试是：

args.toString();

对象无法转换为字符串。

我实现了这个目标：

args[0].toString(); //args[position].toString();

因此我如何解决了我的问题..

Android socket io客户端节点js无法获取值

1 个答案: