Question

我试图操纵包含如下数据的csv文件：

['193T','4234234234'],['30T','54353456346'],['203K','4234234234'],['19E','4234234234']

字母数字字符串应该分成数字和单个字符，然后作为int（）和字符串放回到数组中。然后第二步是聚集所有相同的字符并按整数排序。

结束这样的事情：

[19,'E',4234234234],[203,'K',4234234234],[30,'T',54353456346],[193,'T',4234234234]

我希望你能掌握它背后的想法。

非常感谢你提前帮助。

Answer 1

l = [['193T','4234234234'],
     ['30T','54353456346'],
     ['203K','4234234234'],
     ['19E','4234234234']]

# Using a list comprehension
[[int(i[0][:-1]), i[0][-1], int(i[1])] for i in l]

输出

[[193, 'T', 4234234234],
 [30, 'T', 54353456346],
 [203, 'K', 4234234234],
 [19, 'E', 4234234234]]

然后，您可以使用第二个元素作为key进行排序。

sorted([[int(i[0][:-1]), i[0][-1], int(i[1])] for i in l], key = lambda x: x[1])

输出

[[19, 'E', 4234234234L],
 [203, 'K', 4234234234L],
 [193, 'T', 4234234234L],
 [30, 'T', 54353456346L]]

Answer 2

如果字母字符始终位于字符串的末尾，则可以使用：

>>> entries = (['193T','4234234234'],['30T','54353456346'],['203K','4234234234'],['19E','4234234234'])
>>> entries = tuple([int(entry[0][:-1]), entry[0][-1], entry[1]] for entry in entries)
>>> print entries
([193, 'T', '4234234234'], [30, 'T', '54353456346'], [203, 'K', '4234234234'], [19, 'E', '4234234234'])

Answer 3

import re
from operator import itemgetter
import pprint

# Pretty printer (for nice output)
pp = pprint.PrettyPrinter(indent=4)

# Test data
arr = [
['193T','4234234234'],['30T','54353456346'],['203K','4234234234'],['19E','4234234234']
]

for x in arr:
    # Regex search of string
    m = re.search("(?i)(\d+)([a-z])", x[0])
    if m:
        number = int(m.group(1))
        character = m.group(2)
        x.pop(0)
        x.insert(0, character)
        x.insert(0, number)

# Sort the results
result = sorted(sorted(arr, key=itemgetter(0)), key=itemgetter(1))

pp.pprint(result)

Python - 将字母数字列表分隔为整数和字符串

3 个答案: