Question

以下是我的表数据

time_stamp     Name
01-Mar-14      a
02-Mar-14      b
02-Mar-14      c
01-May-14      d
02-May-14      e
01-Jun-14      f

需要输出：

(3,0,2,1) (Month wise count with 0 if month doesn't exist)

我创建了以下查询：

select 
 listagg(count(1),',') within group (order by EXTRACT(month FROM time_stamp)) 
from ps_bqueues_host 
where time_stamp BETWEEN TO_DATE('01-Mar-14', 'DD-Mon-YY') and
  TO_DATE('01-Jun-14', 'DD-Mon-YY') GROUP BY EXTRACT(month FROM time_stamp)

这给了我输出：

(3,2,1) (Month of Apr with 0 is not there).

请建议如何在所有月份分组。

感谢。

Answer 1

您应该将此原始表格与表格一起加入给定期间内的所有月份。如果是在一年之内，那么we need 1,2,3,...12 sequence。

select 
 listagg(count(Name),',') within 
    group (order by m.rn) 
from 
     (SELECT * FROM  ps_bqueues_host 
      where time_stamp 
        BETWEEN TO_DATE('01-Mar-14', 'DD-Mon-YY') 
        and     TO_DATE('01-Jun-14', 'DD-Mon-YY') 
     )   
RIGHT JOIN 
     (SELECT LEVEL rn FROM dual CONNECT BY LEVEL <= 12) m
     ON m.rn=EXTRACT(month FROM time_stamp)

WHERE m.rn BETWEEN EXTRACT(month FROM TO_DATE('01-Mar-14', 'DD-Mon-YY'))
           AND  EXTRACT(month FROM TO_DATE('01-Jun-14', 'DD-Mon-YY'))
GROUP BY m.rn

SQLFiddle demo

Oracle查询获取月份数据，并提供0月份不可用

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