Question

我有这样的表格：

class CampaignType extends AbstractType {

protected $pricings;

public function __construct(array $pricings){
    $this->pricings = $pricings;
}

public function buildForm(FormBuilderInterface $builder, array $options){

    $builder
        ->setMethod('POST')
        ->add('name', 'text')
        ->add('code', 'text')
        ->add('pricings', 'choice', array(
            'choices' => $this->pricings,
            'expanded' => false,
            'multiple' => true
        ))
        ->add('save', 'submit');
}

}

$ pricing是传递给表单的键值数组。

array(2) { 
    [2335331]=> string(38) "1 Months - 1 Issues - 34 - Credit card" 
    [2335332]=> string(40) "12 Months - 12 Issues - 23 - Credit card" 
    [2335333]=> string(40) "24 Months - 12 Issues - 23 - Credit card" 
}

现在，当我需要编辑记录时，我将$ defaultData传递给表单：

array(10) { 
  ["id"]=> string(1) "4" 
  ["subsite_id"]=> string(3) "104" 
  ["name"]=> string(5) "ffsgd" 
  ["code"]=> string(6) "dfgfdg" 
  ["pricings"]=> 
    array(2) { 
      [2335331]=> string(38) "1 Months - 1 Issues - 34 - Credit card" 
      [2335332]=> string(40) "12 Months - 12 Issues - 23 - Credit card" } }

但是多选不会将传递的选项视为已选择。

有没有办法将多选小部件的几个选项标记为已选中，具体取决于从数据库中获取的键值数组？不使用Doctrine

Answer 1

至于VisioN建议，必须使用'data'选项，只需使用一个简单的选定值数组，而不是我想的键值数组。

所以Form声明看起来像这样：

class CampaignType extends AbstractType {

  protected $pricings;

  public function __construct(array $pricings, array $selectedPricings){
    $this->pricings = $pricings;
    $this->selectedPricings;
  }

  public function buildForm(FormBuilderInterface $builder, array $options){

    $builder
      ->setMethod('POST')
      ->add('name', 'text')
      ->add('code', 'text')
      ->add('pricings', 'choice', array(
        'choices' => $this->pricings,
        'expanded' => false,
        'multiple' => true,
        'data' => $this->selectedPricing      //array('2335331', '2335332')
      ))
      ->add('save', 'submit');
   }
}

symfony2 - 根据来自数据库的数据选择标记选项 - 没有学说

1 个答案: