简单的Java网络IO不适用于大数据

时间:2014-06-09 09:13:44

标签: java io network-programming

我遇到了一个奇怪的问题,它没有出现在MACOS上,只有linux ...... 当我在linux中运行以下代码时,我有时会得到一条不一致的消息。 代码只创建两个线程,其中一个发送大量的字节数组,所有的1到另一个,另一个线程只检查所有内容是否为1。它偶尔发生(似乎它取决于n ..)它收到0。

有人能帮助我吗?

    import java.io.InputStream;
    import java.io.OutputStream;
    import java.net.ServerSocket;
    import java.net.Socket;

    public class TestIO {
        static final int n = 500000;
        final static byte d  = 10;

        static class SenderRunnable implements Runnable {
            SenderRunnable () {}
            private ServerSocket sock;
            protected OutputStream os;

            public void run() {
                try {
                    sock = new ServerSocket(12345);            // create socket and bind to port
                    Socket clientSock = sock.accept();                   // wait for client to connect
                    os = clientSock.getOutputStream();  

                    byte[] a = new byte[10];
                    for(int i = 0; i < 10; ++i)
                        a[i] = d;

                    for (int i = 0; i < n; i++) {
                        os.write(a);
                    }
                    os.flush();

                    sock.close(); 
                } catch (Exception e) {
                    e.printStackTrace();
                    System.exit(1);
                }
            }
        }

        static class ReceiverRunnable implements Runnable {
            ReceiverRunnable () {}
            private Socket sock;
            public InputStream is;
            public void run() {
                try {
                    sock = new java.net.Socket("localhost", 12345);          // create socket and connect
                    is = sock.getInputStream();

                    for (int i = 0; i < n; i++) {
                        byte[] temp = new byte[10];
                        is.read(temp);
                        for(int j = 0; j < 10; ++j)
                            if(temp[j] != d){
                                System.out.println("weird!"+" "+i+" "+j+" "+temp[j]);
                            }
                    }
                    sock.close(); 
                } catch (Exception e) {
                    e.printStackTrace();
                    System.exit(1);
                }
            }
        }


        public static void test1Case() throws Exception {
            SenderRunnable sender = new SenderRunnable();
            ReceiverRunnable receiver = new ReceiverRunnable();
            Thread tSnd = new Thread(sender);
            Thread tRcv = new Thread(receiver);
            tSnd.start(); 
            tRcv.start(); 
            tSnd.join();
            tRcv.join();
        }

        public static void main(String[] args)throws Exception {
            test1Case();
            test1Case();
            test1Case();
            test1Case();
            test1Case();
            test1Case();
            test1Case();
            test1Case();
        }
    }

谢谢!我将部分代码更改为以下内容,现在可以正常工作。

    for (int i = 0; i < n; i++) {
        byte[] temp = new byte[10];
        int remain = 10;
        remain -= is.read(temp);
        while(0 != remain)
        {
            remain -= is.read(temp, 10-remain, remain);
        }
        for(int j = 0; j < 10; ++j)
            if(temp[j] != d){
                System.out.println("weird!"+" "+i+" "+j+" "+temp[j]);
            }
    }

2 个答案:

答案 0 :(得分:0)

你的错误在于读者方面。 方法read()无法保证填充您的数组。它只接收已经可用的字节并返回已经获得的字节数。所以你必须在循环中读取字节,直到read返回-1。

答案 1 :(得分:0)

您应该在调用InputStream.read() http://docs.oracle.com/javase/7/docs/api/java/io/InputStream.html#read(byte[])

时检查读取的实际字节数