Question

我有一个类似

的javascript assoc数组（对象）

aa = {"(one)":["a","b","c"], "(two)":["d","e","f"]}

和

之类的字符串

s = "(two) blah blah (one) etc (two)"

我想将assoc数组转换为一个普通数组，其顺序如字符串

中所指定

newarray = [["d","e","f"] , ["a","b","c"], ["d","e","f"]]

唯一的事情是，数组和字符串可能包含数百万个项目。如果我使用带有全局修饰符的string.match来执行此操作，然后迭代结果，我最终会使用大量内存吗？有没有办法迭代字符串中的匹配而不存储所有匹配的文本（有点像string.search的迭代器版本）？

Answer 1

var aa = {"(one)":["a","b","c"], "(two)":["d","e","f"]};
var s = "(two) blah blah (one) etc (two)"
var newarray = [];
var res = s.match(/\((.*?)\)/g);
var i = 0;
while (i < res.length){
    newarray.push(aa[res[i]]); 
    i++;
}
console.log(newarray);

最后这个完美无缺。

http://jsfiddle.net/KRzRj/

Answer 2

基于正则表达式，我正在思考这些问题：

var aa = {"(one)":["a","b","c"], "(two)":["d","e","f"]};
var s = "(two) blah blah (one) etc (two)";
var result = [];

s.match(/(\(.+?\))/g).forEach(function(match) {
    result.push(aa[match]);
});

从关联数组和长字符串构造javascript数组

2 个答案: