public String POST(String url){
InputStream inputStream = null;
String result = "";
try {
// 1. create HttpClient
HttpClient httpclient = new DefaultHttpClient();
// 2. make POST request to the given URL
HttpPost httpPost = new HttpPost(url);
String json = "";
// 3. build jsonObject
JSONObject jsonObject = new JSONObject();
jsonObject.accumulate("UserName","example@gmail.com");
jsonObject.accumulate("Password","123456!");
// 4. convert JSONObject to JSON to String
json = jsonObject.toString();
// ** Alternative way to convert Person object to JSON string usin Jackson Lib
// ObjectMapper mapper = new ObjectMapper();
// json = mapper.writeValueAsString(person);
// 5. set json to StringEntity
StringEntity se = new StringEntity(json);
// 6. set httpPost Entity
httpPost.setEntity(se);
// 7. Set some headers to inform server about the type of the content
httpPost.setHeader("Accept", "application/json");
httpPost.setHeader("Content-type", "application/json");
// 8. Execute POST request to the given URL
HttpResponse httpResponse = httpclient.execute(httpPost);
Toast.makeText(getBaseContext()," text",Toast.LENGTH_SHORT).show();
// 9. receive response as inputStream
inputStream = httpResponse.getEntity().getContent();
// 10. convert inputstream to string
if(inputStream != null)
result = convertInputStreamToString(inputStream);
else
result = "Did not work!";
} catch (Exception e) {
Log.d("InputStream", e.getLocalizedMessage());
}
// 11. return result
return result;
}
private class HttpAsyncTask extends AsyncTask<String, Void, String> {
@Override
protected String doInBackground(String... urls) {
// Toast.makeText(getBaseContext(), "post invoked", Toast.LENGTH_SHORT).show();
return POST(urls[0]);
}
// onPostExecute displays the results of the AsyncTask.
@Override
protected void onPostExecute(String result) {
Toast.makeText(getBaseContext(), "Data Sent!"+result+" don", Toast.LENGTH_LONG).show();
}
}
我尝试从HTTPAsyncTask类的对象调用此POST方法,并传递了目标url。但是,OnPostExecute()中的Toast突然出现了消息&#34; Data sent!Done&#34;,它告诉了&#39;结果&#39;变量为null。在log cat中显示&#34;我从logcat获得反馈&#34;请求时间失败,Java.net.socketException:协议不支持Addres系列&#34;。那会是什么错?任何人都可以解决这个***
答案 0 :(得分:0)
尝试将此添加到AndroidManifest.xml
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
请抓住这个例外:
catch(SocketException se)
{
Log.e("Exception ---- : " , "Error on execute??" + se.getMessage());
se.printStackTrace();
}
答案 1 :(得分:0)
URL缺少协议部分。尝试
http://devcare.dyndns.info:85/WCFServices/UserAuthServices.svc/Login
否则devcare.dyndns.info
将被误认为是协议。