Question

我确实有一个要求，比如我需要用sysdate来计算一个人的年龄。使用sysdate计算人员年龄应该大于或小于75岁和09个月。但在一些scnearios它没有成功。可以帮助解决这个问题。

IF TO_CHAR(bday,'mm/dd')='02/29' THEN
age = ADD_MONTHS(bday-1,12*75);
ELSE
age = ADD_MONTHS(bday,12*75);
END IF;

但这在某些情况下无效。任何人都可以帮助满足这一要求

Answer 1

试试这个：

查找年份：查找当前日期与DOB之间的总天数，并将其除以365。

查找月份：查找剩余天数并将其除以30。

DECLARE @DOB DATETIME
DECLARE @Days INT  
DECLARE @Year INT
DECLARE @Month INT
DECLARE @DaysRemaining INT

SET @DOB ='9/4/1938'
SET @Days = DATEDIFF(DAY,@DOB,GETDATE())
SET @Year = @Days / 365
SET @DaysRemaining = @Days - (365 * @Year)
SET @Month = @DaysRemaining / 30

SELECT @DOB AS DOB, CAST(@Year AS VARCHAR) + ' years ' + CAST(@Month AS VARCHAR) + ' months' AS Age

尝试使用此逻辑并应用您的条件。

Answer 2

DATEDIFF - 减去两个日期会对您有所帮助。

请在此处查看示例： -

http://answers.oreilly.com/topic/163-how-to-calculate-the-interval-between-two-dates-or-times-in-mysql/

http://dev.mysql.com/doc/refman/5.0/en/date-calculations.html

Answer 3

DECLARE @DOB DATETIME
DECLARE @RequiredAgeInMonths INT  
DECLARE @ActualAgeInMonths INT

SET @DOB ='9/4/1938'
SET @RequiredAgeInMonths=909
SET @ActualAgeInMonths = (SELECT DATEDIFF(MM,@DOB,GETDATE()))

IF(@ActualAgeInMonths = @RequiredAgeInMonths)
PRINT 'YOUR AGE IS 75 YEARS AND 9 MONTHS'

ELSE 
 PRINT 'YOUR AGE IS NOT EQUAL TO 75 YEARS AND 9 MONTHS'

在SQL中计算具有月和年的年龄

3 个答案: