我处在这样一种情况:我想写一些东西(用打孔和打孔写出员工的详细信息)到一个文件中并将其读回(以显示所有员工穿孔和打孔的人的报告)。
package Test;
import java.io.*;
import java.text.*;
import java.util.*;
public class Test {
public static void main(String[] args) throws IOException {
String lastName = "";
String firstName = "";
String choice = "y";
String customerChoice = "x";
int empid = 0;
Scanner sc = new Scanner(System.in);
int currentIndex;
File file = new File("E:/output.txt");
FileWriter fw = new FileWriter(file.getAbsoluteFile());
BufferedWriter bw = new BufferedWriter(fw);
DateFormat dateFormat = new SimpleDateFormat("yyyy/MM/dd HH:mm:ss");
Calendar cal = Calendar.getInstance();
int[] punchedArray;
punchedArray = new int[100];
// System.out.println(t);
while (!customerChoice.equalsIgnoreCase("d") && customerChoice != "invalid" && choice.equalsIgnoreCase("y")) {
customerChoice = getValidCustomerChoice(sc);
if (customerChoice.equalsIgnoreCase("a")) {
// System.out.println("In Create Customer");
System.out.print("Enter your first name: ");
firstName = sc.next();
System.out.print("Enter your last name: ");
lastName = sc.next();
System.out.println(firstName + lastName + "with employee id" + empid);
//System.out.println(firstNameArray[newEmployeeIndex] + " " + lastNameArray[newEmployeeIndex] + " your employee ID is: " + employeeIDArray[newEmployeeIndex]);
empid++;
//sc.next();
}
if (customerChoice.equalsIgnoreCase("b")) {
System.out.println("Welcome to the punch in/out screen"+"\n");
System.out.print("Enter your employee ID: ");
currentIndex = Integer.parseInt(sc.next());
if (punchedArray[currentIndex] == 0)
{
System.out.println("You are now punched in");
punchedArray[currentIndex] = 1;
}
else if (punchedArray[currentIndex] == 1)
{
System.out.println("You are now punched out");
punchedArray[currentIndex] = 0;
}
System.out.print(firstName + " "+ lastName + " "+ "your employee ID is " + currentIndex + " and your clock date and time is: " + " "+ cal.getTime() +"\n");
String content = firstName + lastName + empid + cal.getTime();
bw.write(content);
bw.newLine();
bw.close();
}
if (customerChoice.equalsIgnoreCase("c")) {
System.out.print("Welcome to the report screen." + "\n");
System.out.print("Enter your selection (I = individual report or A= all employees):" + "\n");
customerChoice = sc.next();
if (customerChoice.equalsIgnoreCase("i")) {
System.out.println("In Individual Report");
} else if (customerChoice.equalsIgnoreCase("a")) {
System.out.println("In Consoldated Report");
}
}
if(customerChoice.equalsIgnoreCase("d"))
{
//bw.close();
break;
}
}
}
public static String getValidCustomerChoice(Scanner sc) {
String customerChoice = "";
// sc.nextLine();
boolean isValid = false;
int invalidCounter = 0;
System.out.print("Enter your selection (a= Add New Employee, b = Punch in/out, c= Report, d = Exit):");
while (isValid == false && invalidCounter < 3) {
customerChoice = sc.next();
if (!customerChoice.equalsIgnoreCase("a")
&& !customerChoice.equalsIgnoreCase("b") && !customerChoice.equalsIgnoreCase("c") && !customerChoice.equalsIgnoreCase("d") && !customerChoice.equalsIgnoreCase("I") && !customerChoice.equalsIgnoreCase("A")) {
System.out.println("Invalid choice. Try again.\n");
invalidCounter++;
} else {
isValid = true;
}
sc.nextLine();
}
if (invalidCounter >= 3) {
System.out.println("Invalid three times. Program Exiting.\n");
return "invalid";
}
return customerChoice;
}
}
在第[75]行bw.write(content)我正在写一个名为“output.txt”的文件(我还想为我写入文件的那些员工添加时间戳)。但不知何故,数据不会进入文件,我确信我在关闭它的某个地方犯了一个错误,我想从我写的同一个文件中读取。有人可以建议我哪里出错了吗?
添加更多详情:
run:
Enter your selection (a= Add New Employee, b = Punch in/out, c= Report, d = Exit):a
Enter your first name: Sa
Enter your last name: Ka
SaKawith employee id0
Enter your selection (a= Add New Employee, b = Punch in/out, c= Report, d = Exit):b
Welcome to the punch in/out screen
Enter your employee ID: 0
You are now punched in
Sa Ka your employee ID is 0 and your clock date and time is: Sun Jun 08 20:19:42 EDT 2014
Enter your selection (a= Add New Employee, b = Punch in/out, c= Report, d = Exit):a
Enter your first name: Ka
Enter your last name: Ma
KaMawith employee id1
Enter your selection (a= Add New Employee, b = Punch in/out, c= Report, d = Exit):b
Welcome to the punch in/out screen
Enter your employee ID: 1
You are now punched in
Ka Ma your employee ID is 1 and your clock date and time is: Sun Jun 08 20:19:42 EDT 2014
Enter your selection (a= Add New Employee, b = Punch in/out, c= Report, d = Exit):c
Welcome to the report screen.
Enter your selection (I = individual report or A= all employees):
a
In Consoldated Report
Enter your selection (a= Add New Employee, b = Punch in/out, c= Report, d = Exit):BUILD STOPPED (total time: 1 minute 8 seconds)
所以,当我现在去我的Pc的E驱动器时,我只看到一个名为output.txt的文件(最新修改时间),但它没有任何内容。我试图在循环后关闭我的缓冲区,但没有运气。另外,请告知阅读我写入文件的数据
请指教!
由于
答案 0 :(得分:0)
我不确定我是否理解你的问题,但是像这样,你只能写一次文件,因为你写完之后关闭它。相反,您可以使用flush()方法来确保将内容写入文件。
请考虑阅读http://docs.oracle.com/javase/7/docs/api/java/io/BufferedWriter.html上的文档。
答案 1 :(得分:0)
在我的测试中,它工作正常。但改变bw.close();到bw.flush();因为输出流将在第一次输入后关闭。并且第二个输入你有例外
答案 2 :(得分:-1)
立即开始我建议尝试用E:\output.txt
替换您的文件名。我相信Windows文件路径使用反斜杠。