我试图编写一个将数字转换为单词的代码，最多可达999万亿。到目前为止，这是我的代码。它可以达到119，但之后就会变得凌乱。我无法使用追加或枚举。我一直坚持如何打印更大的数字;我如何格式化数字，如978,674,237,105？
NUMBERS = ["zero", "one", "two","three","four","five","six","seven","eight","nine",
"ten","eleven","twelve","thirteen","fourteen","fiveteen","sixteen",
"seventeen","eightteen","nineteen"]
TENS = ["", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty",
"ninety"]
HUNNITS = ["","hundred","thousand","million","billion","trillion"]
n = eval(input("What is the number the you want to convert? "))
def convert():
if n >= 20:
tens = n // 10
units = n % 10
if units != 0:
result = TENS[tens] + "-" + NUMBERS[units]
else:
result = TENS[tens]
else:
result = NUMBERS[n]
print (result)
def convert2():
if n >=100:
tens2 = n//100
units2 = n%100
if units2 != 0:
result2 = HUNNITS[tens2] + "-" + TENS[tens2] + "and" + NUMBERS[units2]
else:
result2 = HUNNITS[tens2]
else:
result2 = HUNNITS[n]
print(result2)
def main():
if n >=20 and n< 100:
x = convert()
if n >=100:
y = convert2()
main()
答案 0 :(得分：1)
我不想劝阻你，但这个问题已经解决了。有一个简洁的Python模块来执行此操作，称为num2words
以下是link to the GitHub repository
here is the actual script用于英语（它支持多种语言）。如果仍然需要，你可以获得一些灵感来修复你的脚本。
答案 1 :(得分：0)
我使用原始列表并使用python 2为项目euler编写了这个。可能有很多错误我没有对它进行过多的测试，但它应该有助于你们
nums = ["", "one", "two", "three", "four", "five",
"six", "seven", "eight", "nine "]
teens = ["", "eleven", "twelve", "thirteen", "fourteen",
"fifteen", "sixteen", "seventeen", "eighteen", "nineteen"]
tens = ["", "ten", "twenty", "thirty", "forty",
"fifty", "sixty", "seventy", "eighty", "ninety"]
thousands = ["","thousand", "million", "billion", "trillion"]
def num_to_words():
n= int(input("Enter number to convert: "))
words = ""
if n == 0:
words += "zero"
else:
numStr = "%d" % n
groups = (len(numStr) + 2) // 3
numStr = numStr.zfill(groups * 3)
for i in range(0, groups*3, 3):
h = int(numStr[i])
t = int(numStr[i+1])
u = int(numStr[i+2])
g = groups - (i // 3 + 1)
if h >= 1:
words += nums[h]
words += " hundred "
words+=" "
if int(numStr) % 100: # if number modulo 100 has remainder add "and" i.e one hundred and ten
words+=" and "
if t > 1:
words+= tens[t]
if u >= 1:
words+= nums[u]
words+=" "
elif t == 1:
if u >= 1:
words+= teens[(u)]
else:
words+= tens[t]
words+=" "
else:
if u >= 1:
words+= nums[u]
words+=" "
if g >= 1 and (h + t + u) > 0:
words+= thousands[g]
words+=" "
return words
In [7]: num_to_words()
Enter number to convert: 12399990
Out[7]: 'twelvemillion three hundred and ninetynine thousand nine hundred and ninety'
答案 2 :(得分：0)
这可以很容易地递归完成：
def as_words(n):
"""Convert an integer n (+ve or -ve) to English words."""
# lookups
ones = ['zero', 'one', 'two', 'three', 'four',
'five', 'six', 'seven', 'eight', 'nine',
'ten', 'eleven', 'twelve', 'thirteen', 'fourteen',
'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen']
tens = ['zero', 'ten', 'twenty', 'thirty', 'forty',
'fifty', 'sixty', 'seventy', 'eighty', 'ninety']
# negative case
if n < 0:
return "minus {0}".format(as_words(abs(n)))
# 1000+
for order, word in [(10**12, "trillion"), (10**9, "billion"),
(10**6, "million"), (10**3, "thousand")]:
if n >= order:
return "{0} {1}{2}".format(as_words(n // order), word,
" {0}".format(as_words(n % order))
if n % order else "")
# 100-999
if n >= 100:
if n % 100:
return "{0} hundred and {1}".format(as_words(n // 100),
as_words(n % 100))
else:
return "{0} hundred".format(as_words(n // 100))
# 0-99
if n < 20:
return ones[n]
else:
return "{0}{1}".format(tens[n // 10],
"-{0}".format(as_words(n % 10))
if n % 10 else "")
答案 3 :(得分：0)
这在Python 3.x中适用于我：
print('Type any number here: ')
number = input()
int_side = number
dec_side = ''
for i in range(0, len(number)):
if number[i] == '.':
int_side = number[:i]
dec_side = number[i + 1:]
break
while not (int_side.isdigit()) or not (dec_side.isdigit()) and dec_side != '':
dec_side = ''
print('Only numbers are allowed! (decimals included, but not fractions)')
print('Type any number here: ')
number = input()
int_side = number
for i in range(0, len(number)):
if number[i] == '.':
int_side = number[:i]
dec_side = number[i + 1:]
user_choice = input()
int_length = len(int_side)
ones = ['', 'one ', 'two ', 'three ', 'four ', 'five ', 'six ', 'seven ', 'eight ', 'nine ']
teens = ['ten ', 'eleven ', 'twelve ', 'thirteen ', 'fourteen ', 'fifteen ', 'sixteen ', 'seventeen ', 'eighteen ',
'nineteen ']
decades = ['', '', 'twenty ', 'thirty ', 'forty ', 'fifty ', 'sixty ', 'seventy ', 'eighty ', 'ninety ']
hundreds = ['', 'one hundred ', 'two hundred ', 'three hundred ', 'four hundred ', 'five hundred ', 'six hundred ',
'seven hundred ', 'eight hundred ', 'nine hundred ']
comma = ['thousand, ', 'million, ', 'trillion, ', 'quadrillion, ']
word = ''
int_length = len(int_side)
dec_length = len(dec_side)
change = int_length
up_change = 0
while change > 0:
if int_side == '':
break
if number == '0':
word = 'zero'
break
elif change > 1 and int_side[change - 2] == '1':
for i in range(0, 10):
if int_side[change - 1] == str(i):
word = teens[i] + word
else:
if change > 0:
for i in range(0, 10):
if int_side[change - 1] == str(i):
word = ones[i] + word
if change > 1:
for i in range(0, 10):
if int_side[change - 2] == str(i):
word = decades[i] + word
if change > 2:
for i in range(0, 10):
if int_side[change - 3] == str(i):
word = hundreds[i] + word
if change > 3:
word = comma[up_change] + word
change -= 3
up_change += 1
word += 'point '
for i in range(0, len(dec_side)):
for x in range(0, 10):
if dec_side[i] == str(x):
word += ones[x]
print(word)
这是一个例子：
Type any number here: 13243214.1324hk
Only numbers are allowed! (decimals included, but not fractions)
Type any number here: 13243214.1324
thirteen million, two hundred forty three thousand, two hundred
fourteen point one three two four