Question

我有这个字符串：＆＃34;一，二，三，四，＆＃34; 我想做的是得到一个＆＃34;，＆＃34;两个＆＃34;，＆＃34;三个＆＃34;在数组空间中，所以当我打印数组时，我得到了一个＆＃34;一个＆＃34; ＆＃34; 2＆＃34; ＆＃34;三＆＃34 ;.我有这个代码，但我得到的只是＆＃34; eeeeeeeeeeeeeeeeeee＆＃34;

 for(int j=0;j<s.length();j++){
    for(int i=0;i<s.length();i++)
        if(Character.isLetter(s.charAt(i))&&s.charAt(i)!=',')
        words[j]=""+s.charAt(i);
    }

Answer 1

然后试试这个

   String test = " one, ,two three,4,";
    //replace all digit to blank
    test = test.replaceAll("\\d+", "");
    List<String> splittedText = Splitter.on(",").omitEmptyStrings().trimResults().splitToList(test);
    String combineWords = "";
    for (String word : splittedText) {
        combineWords+=word+" ";
    }

    List<String> finalSplittedWord = Splitter.on(" ").omitEmptyStrings().splitToList(combineWords);
    for (String word : finalSplittedWord) {
        System.out.println(word);
    }

输出

  one
  two
  three

Splitter.on来自Google Guava图书馆。下载jar＆amp;在项目中使用它

Answer 2

这是我的尝试。此方法适用于每种语言和每个空格字符：

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

public class Split {

    public static void main(String[] args) {
        String str = " one, two, three, 4,";
        System.out.println(getWords(str));
    }

    public static List<String> getWords(String str) {
        List<String> list = new ArrayList<String>(Arrays.asList(str
            .split("[,\\s+]")));
        list.removeIf(s -> s.isEmpty()
            || !s.chars().allMatch(c -> Character.isAlphabetic(c)));
        return list;
    }
}

输出：

[one, two, three]

但它只能在Java 8中运行。如果你需要它在Java 7中工作，它会更长一点：

import java.util.ArrayList;
import java.util.Arrays;
import java.util.Iterator;
import java.util.List;

public class Split {
    public static void main(String[] args) {
        String str = " one, two, three, 4,";
        System.out.println(getWords(str));
    }

    public static List<String> getWords(String str) {
        List<String> list = new ArrayList<String>(Arrays.asList(str.split("[,\\s+]")));

        Iterator<String> it = list.iterator();

        while (it.hasNext()) {
            String part = it.next();
            if (part.isEmpty()) {
                it.remove();
                continue;
            }

            for (int i = 0; i < part.length(); i++) {
                if (!Character.isAlphabetic(part.charAt(i))) {
                    it.remove();
                    continue;
                }
            }
        }

        return list;
    }
}

输出：

[one, two, three]

Answer 3

使用String.split()方法：

String[] words = s.split(",");

编辑：如果你的字符串完全像＆＃34;一，二，三，四，＆＃34;，看起来你正在寻找整个单词。这应该有所帮助：

String s = " one, ,two three,4,";
Pattern p = Pattern.compile("([a-zA-Z]+)");
Matcher m = p.matcher(s);
List<String> stringList = new ArrayList<String>();
while (m.find()) {
    stringList.add(m.group(1));
}
String[] words = stringList.toArray(new String[stringList.size()]);

从数组中提取单词

3 个答案: