Question

我不知道＆＃34;无法访问的代码＆＃34;是什么意思？

我的代码double probabilityOfWin = wins / (wins + loses);的最后一行显示了无法访问的代码。

import java.util.Random;

 public class CrapsGame {
    public static final int GAMES = 9999;

public static void main(String[] args) {
    Random randomGenerator1 = new Random();
    Random randomGenerator2 = new Random();
    Random randomGenerator3 = new Random();
    Random randomGenerator4 = new Random();

    int dice1 = randomGenerator1.nextInt(6) + 1;
    int dice2 = randomGenerator2.nextInt(6) + 1;

    int comeoutSum = dice1 + dice2;
    int point = 0;

    // The comeout roll

    if (comeoutSum == 7 || comeoutSum == 12)
        System.out.println("wins");
    else if ( comeoutSum == 2 || comeoutSum == 3 || comeoutSum == 12)
        System.out.println("loses");
    else
         point = comeoutSum;

    int wins = 0;
    int loses = 0;


    while(GAMES <= 9999)
    {
        dice1 = randomGenerator3.nextInt(6) + 1;
        dice2 = randomGenerator4.nextInt(6) + 1;
        int sum = dice1 + dice2;

        if (sum == point)
            wins++;
        else if (sum == 7)
            loses++;
    }

    double probabilityOfWin = wins / (wins + loses);


}

}

Answer 1

这个循环在这里：

while(GAMES <= 9999)
{
    ...
}

解析为while (true)，因为永远不会修改GAMES的值。因此，之后的任何代码（在您的情况下为double probabilityOfWin = wins / (wins + loses);）都被视为无法访问。

Answer 2

您没有对常量GAME进行任何更改。所以while循环永远不会终止。最后一行代码无法访问。无法访问意味着代码永远不会被执行。例如，

return 15;
int a = 12;

然后最后一行代码将不会被执行，因为该函数已经返回。

Java中无法访问的代码

2 个答案: