Question

我已经在整个网站上看到了这一点，但仍然无法解决我的问题。这是我唯一的错误，我不知道如何解决这个问题。我已经尝试评论代码的不同部分，只是为了看看会发生什么，但仍然只是错误。发生了什么事？

她也是构建错误

错误C2084：功能＆＃39; HeroProfile :: HeroProfile（无效）＆＃39;已经有一个身体

Main.cpp

#include <iostream>
#include <string>

#include "HeroProfile.h"

using namespace std;

int main()
{
string name;
int race;
double weight;

    cout << "Enter your Hero's name:";
cin>> name;
cout << "Enter your Hero's Race (1:Elf 2:Human 3 Dwarf)";
cin >> race;
cout << "Enters your Hero's weight ( in pounds):";
cin >> weight;

HeroProfile Hero_1(name, race, weight);

cout << endl << "hero's Name: " << Hero_1.getName() << endl <<
    "Race: " << Hero_1.getRace() << endl <<
    "Weight:" << Hero_1.getWeight() << endl;

cout << endl;

cout << "Enter your Hero's Name:";
cin >> name;
cout << "Enter your Race (1:Elf 2:Human 3 Dwarf)";
cin >> race;
cout <<"Enter your Hero's weight (in pounds)";
cin >> weight;

HeroProfile Hero_2(name, race, weight);

Hero_2.setName(name);
Hero_2.setRace(race);
Hero_2.setWeight(weight);

cout << endl << "Hero's Name: " << Hero_2.getName() << endl <<
    "Race: " << Hero_2.getRace() << endl << "Weight: " << Hero_2.getWeight() <<     endl;

return 0;
}

标题文件

#include <iostream>
#include <string>

using namespace std;

#ifndef HeroProfiel_H 
#define HeroProfile_H

class HeroProfile 
{

public:
    //default constructor
    HeroProfile();

    //overlaod constructor
    HeroProfile(string, int, double);

    //destructor
    ~HeroProfile();

    //Accesor functions
    string getName() const;
        // get name - returns name of patient

    int getRace() const;
        // getHeight-returns height of patient

    double getWeight() const;
        // getWeight- returns weight of patient

    //Mutator Functions
    void setName(string);
        //set name of patient
        //@param string - name of patient

    void setRace(int);
        //setHeight-sets heigh tof patient
        //@param int- height iof patient

    void setWeight(double);
    //setWeight-sets weight of patiend
    //@param double-weight of patient



private:
    //Memeber variables
    string newName;
    int newRace;
    double newWeight;




};

#endif

和第二个.cpp文件

#include "HeroProfile.h"

eroProfile::HeroProfile() //Default constructor
{
newRace = 0;
newWeight = 0.0;
}

HeroProfile::HeroProfile(string name, int race, double weight) //Overloaded Constructor
{
newName = name;
newRace = race;
newWeight = weight;
}

HeroProfile::HeroProfile()
}
}

//Accessors
string HeroProfile::getName() const 
{
return newName;
}

int HeroProfile::getRace() const 
{
return newRace;
}

double HeroProfile::getWeight() const
{
return newWeight;
}

//Mutators
void HeroProfile::setName(string name)
{ 
newName = name;
}

void HeroProfile::setRace(int race)
{
newRace = race;
}


void HeroProfile::setWeight(double weight)
{
newWeight = weight;
}

Answer 1

这条消息正是它所说的。忽略拼写错误，第二个.cpp中的第一个和第三个定义属于同一个函数。

Answer 2

正如其他人所说，你的第二个cpp文件中有HeroProfile默认构造函数HeroProfile::HeroProfile()的2个定义：

第一个是

HeroProfile::HeroProfile() //Default constructor
{
newRace = 0;
newWeight = 0.0;
}

，第二个是

HeroProfile::HeroProfile()
}
}

根据我没有看到的事实，你可能打算让第二个成为你的类析构函数（在头文件中声明但在cpp文件中没有定义），在这种情况下你应该替换它有这个：

HeroProfile::~HeroProfile()
}
}

我希望你不会因为HeroProfile::HeroProfile(void)和HeroProfile::HeroProfile()是同一件事而感到困惑，所以我想我应该指出它。

错误C2084功能已经有一个正文

2 个答案: