Question

我真的很难用SQL查询来只返回重复的行，例如：

EMPLOYEE_ID   STORE_NO   REGION
2531047     1671         E05
2544970     1254         W09
2566618     1625         E01
2566618     1635         E01
2566618     1835         E01

Should look like:

EMPLOYEE_ID   STORE_NO   REGION
2566618     1625         E01
2566618     1635         E01
2566618     1835         E01

以上是通过以下方式实现的：

SELECT 
   E.EMPLOYEE_ID,
   E.STORE_NO,
   S.REGION
FROM 
   [USICOAL].[dbo].[EMPLOYEE_STR_ASGN] AS E
RIGHT JOIN 
   [USICOAL].[dbo].[STORE] AS S ON E.STORE_NO = S.STORE_NO
ORDER BY EMPLOYEE_ID, REGION

我尝试了各种选项，但只能找到一种方法来删除这些重复项，而不是仅显示它们......任何人都可以建议上述内容是否可行？

提前致谢，查理。

Answer 1

SELECT * FROM stuff st
WHERE EXISTS (
        SELECT 1 FROM stuff xx
        WHERE xx.employee_id = st.employee_id
        GROUP BY xx.employee_id
        HAVING COUNT(*) > 1
        )
        ;

Answer 2

SELECT 
   E.EMPLOYEE_ID,
   E.STORE_NO,
   S.REGION
FROM 
   [USICOAL].[dbo].[EMPLOYEE_STR_ASGN] AS E
RIGHT JOIN 
   [USICOAL].[dbo].[STORE] AS S ON E.STORE_NO = S.STORE_NO 
JOIN 
   ( SELECT EMPLOYEE_ID 
       FROM [USICOAL].[dbo].[EMPLOYEE_STR_ASGN] 
      GROUP BY EMPLOYEE_ID 
     HAVING COUNT(*) > 1 ) DUPS 
 ON DUPS.EMPLOYEE_ID = E.EMPLOYEE_ID
ORDER BY E.EMPLOYEE_ID, REGION

正确的加入可能只是一个加入如果有> 1名员工有> 0名员工

显示重复记录（SQL）

2 个答案: