Question

我有一个

形式的json对象

{
    "key1": ["value4"],
    "key2": ["value1","value2","value3"],
    "key3": ["value5","value6"]
}

我想根据看起来像

的值的数量对它们进行排序

{
    "key2": ["value1","value2","value3"],
    "key3": ["value5","value6"],
    "key1": ["value4"]
}

任何人都可以帮助我。

Answer 1

我建议根据您的数据创建一个新数组并改为使用它：

var json = {
  "key1": ["value4"],
  "key2": ["value1", "value2", "value3"],
  "key3": ["value5", "value6"]
};

$scope.items = [];

function fillItems() {
  for (var key in json) {
    if (json.hasOwnProperty(key)) {
      $scope.items.push({
        key: key,
        values: json[key]
      });
    }
  }
}

fillItems();

HTML：

<div ng-repeat="item in items | orderBy:'values.length':true">
  Key: {{ item.key }} Values: {{ item.values }}
</div>

演示： http://plnkr.co/edit/WnII9LoQX3oHztXtzoLx?p=preview

Answer 2

这是我的解决方案，问题是我无法更改键名，但它按数组的长度对值进行排序。因此，如果键名无关紧要，这对您有用，但如果您想对键进行排序，则需要创建一个新数组。

var obj = {
    "key1": ["value4"],
    "key2": ["value1","value2","value3"],
    "key3": ["value5","value6"]
}
//property count of your object
var length = Object.keys(obj).length;

var j;
var flag = true;   // set flag to true to begin first pass
var temp;   //holding variable

while ( flag )
{
    flag= false;    //set flag to false awaiting a possible swap
    for( j=0;  j < length -1;  j++ )
    {
        if ( obj[Object.keys(obj)[j]].length < obj[Object.keys(obj)[j+1]].length )   // change to > for ascending sort
        {
            temp = obj[Object.keys(obj)[j]];//swap elements

            obj[Object.keys(obj)[j]] = obj[Object.keys(obj)[j+1]];
            obj[Object.keys(obj)[j+1]] = temp;

            flag = true; //shows a swap occurred  


        } 
    } 
}

Angularjs根据值的数量对元素进行排序

2 个答案: