我知道一个事实我错过了一些非常小的东西,但我似乎无法让我的代码编译而没有错误。我试图让文本字段采用十进制数字OnClick
,它会吐出数字二进制数。
它一直告诉我初始化Binary但是如果我将它设置为0,那么Binary' 0'而不是转换十进制数。
任何帮助都会很棒!这是我的MainActivity.java文件:
public class MainActivity extends ActionBarActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
if (savedInstanceState == null) {
getSupportFragmentManager().beginTransaction()
.add(R.id.container, new PlaceholderFragment()).commit();
}
final EditText editDecimal = (EditText) findViewById(R.id.editDecimal);
final EditText editBinary = (EditText) findViewById(R.id.editBinary);
Button buttonConvert = (Button) findViewById(R.id.buttonConvert);
buttonConvert.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View arg0) {
int decimal = Integer.valueOf(editDecimal.getText().toString());
int binary;
editBinary.setText(Integer.toBinaryString(binary));
}
});
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.main, menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();
if (id == R.id.action_settings) {
return true;
}
return super.onOptionsItemSelected(item);
}
/**
* A placeholder fragment containing a simple view.
*/
public static class PlaceholderFragment extends Fragment {
public PlaceholderFragment() {
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container,
Bundle savedInstanceState) {
View rootView = inflater.inflate(R.layout.fragment_main, container,
false);
return rootView;
}
}
}
答案 0 :(得分:2)
您不需要变量binary
。相反,你只需要这样做:
editBinary.setText(Integer.toBinaryString(decimal));