Question

我一直在尝试使用java来提取程序中的一些zip文件并将它们放在正确的目录中。我一直在寻找这个参考： http://javabeginnerstutorial.com/code-base/how-to-extract-zip-file-with-subdirectories/

我当前的代码看起来像

                String ziplocation = "/home/user/folder/";
                String zipfile = "libraries.zip";
                String liblocation = "/home/user/folder";

                ZipEntry zipentry;

                if (!zipentry.isDirectory())
                {
                    File fileFile = new File(liblocation + "/" + zipentry.getName());

                    InputStream inputstream = zipfile.getInputStream(zipentry);
                    String str = new java.util.Scanner(inputstream).useDelimiter("/A").next();

                    BufferedWriter bw = new BufferedWriter(new FileWriter(fileFile));
                    bw.append(str);
                    bw.close();

                }

似乎所有东西都从上面的参考文献中正确改编，但是当我编译它时，它给了我：

Exception in thread "main" java.lang.Error: Unresolved compilation problem: 
The method getInputStream(ZipEntry) is undefined for the type String

at Main.main(Main.java:53)

编辑：

我现在已将其更改为

                String ziplocation = "/home/user/folder/zipfile.zip";
                String liblocation = "/home/user/folder/";

                File file = new File(ziplocation);
                ZipFile zipfile = new ZipFile(file);
                InputStream inputStream = new BufferedReader(new FileReader(zipfile));

                ZipEntry zipentry;

                if (!zipentry.isDirectory())
                {
                    File fileFile = new File(liblocation + "/" + zipentry.getName());

                    InputStream inputstream = zipfile.getInputStream(zipentry);
                    String str = new java.util.Scanner(inputstream).useDelimiter("/A").next();

                    BufferedWriter bw = new BufferedWriter(new FileWriter(fileFile));
                    bw.append(str);
                    bw.close();

                }

但是现在编译器正在响应：

Exception in thread "main" java.lang.Error: Unresolved compilation problems: 
Type mismatch: cannot convert from BufferedReader to InputStream
The constructor FileReader(ZipFile) is undefined

at Main.main(Main.java:48)

Answer 1

这意味着字符串对象没有getInputStream方法。在这一行： zipfile.getInputStream（ZipEntry的）;

zipfile是一个字符串。

你需要类似的东西 InputStream inputStream = new BufferedReader（new FileReader（zipfile））;

这里对IO流进行了很好的讨论：http://docs.oracle.com/javase/tutorial/essential/io/streams.html

Answer 2

问题在于：

InputStream inputStream = new BufferedReader(new FileReader(zipfile));

该句子不在您关注的示例中。相反，在 zipfile 中找到的元素有一个循环：

File file = new File(zipFileLocation);
ZipFile zipfile = new ZipFile(file);

ZipEntry zipentry;

System.out.println("nList of files in zip archive");
int fileNumber = 0;
for (Enumeration<? extends ZipEntry> e = zipfile.entries(); e
        .hasMoreElements(); fileNumber++) {
    zipentry = e.nextElement();

    if (!zipentry.isDirectory()) {
...

在Java中提取Zip的问题

2 个答案: