Question

这是我想要做的：

我创建了类用户，其中包含以下内容：

public class User {

private String name;
private String gender;
private int age;

public User() {
    super();
}
public String getName() {
    return name;
}
public void setName(String name) {
    this.name = name;
}
public String getGender() {
    return gender;
}
public void setGender(String gender) {
    this.gender = gender;
}
public int getAge() {
    return age;
}
public void setAge(int age) {
    this.age = age;
}
@Override
public String toString() {
    return "User [name=" + name + ", gender=" + gender + ", age=" + age
            + "]";
}
}

在Activity UserIntro中，用户可以输入姓名，年龄和性别，我想在User中设置这些值，然后在其他Activity中显示。后者我也希望在SQLite中存储这些信息，但现在可以了。

UserInfoActivity 如下所示：

public class UserIntroActivity extends Activity {

public boolean started;
EditText userName;
ImageButton girl;
ImageButton boy;
EditText age;
String pol;
String name;
int userAge;

User user = new User();

public boolean isStarted() {
    return started;
}

public void setStarted(boolean started) {
    this.started = started;
}

@Override
protected void onCreate(Bundle savedInstanceState) {
    // TODO Auto-generated method stub
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_user_intro);

    girl = (ImageButton) findViewById(R.id.imageButtonGirl);
    boy = (ImageButton) findViewById(R.id.imageButtonBoy);
    age = (EditText) findViewById(R.id.editTextAge);

    Button btnGo = (Button) findViewById(R.id.buttonNext);

    girl.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            pol = "zensko";
            user.setGender(pol);

        }
    });

    boy.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            pol = "musko";

        }

    });

    btnGo.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View arg0) {
            userName = (EditText) findViewById(R.id.editTextName);

            Intent intent = new Intent(UserIntroActivity.this,
                    EnterActivity.class);
            startActivity(intent);

            name = userName.getText().toString();
            userAge = Integer.parseInt(age.getText().toString());
            user.setName(name);
            user.setAge(userAge);

            Log.d("USER", name + " , " + userAge + " , " + pol);

            finish();
        }
    });
    }
}

在 EnterActivity 中，我会显示名称，a和性别。

public class EnterActivity extends Activity {
User user = new User();

@Override
protected void onCreate(Bundle savedInstanceState) {
    // TODO Auto-generated method stub
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_enter);


    TextView test = (TextView) findViewById(R.id.textView1);

    test.setText("ime: " + user.toString());

}

}

但是当我这样做时，结果是null，0，null所以我看到user.set ...（）没有设置值。有谁知道为什么以及如何解决问题？谢谢大家！

Answer 1

Google可以通过小搜索告诉您。

Intent intent= new Intent(this,EnterActivity .class);
intent.putExtra("txt", txtview.getText().toString());
startActivity(intent);

然后检索你的文字：

String receive = getActivity().getIntent().getExtras().getString("txt");

Android：如何在其他活动中从textView设置信息

1 个答案: