我在PostgreSQL
中创建了一个函数以插入以下
CREATE TABLE gtab83
(
orderid integer NOT NULL DEFAULT nextval('seq_gtab83_id'::regclass),
acid integer,
slno integer,
orderdte date
)
并创建了Function
CREATE OR REPLACE FUNCTION funcInsert(iacid int,islno int,idate date) RETURNS int AS
$$
declare id_val int;
BEGIN
INSERT INTO GTAB83 (acid,slno,orderdte) VALUES (iacid,islno,idate) RETURNING orderid
into id_val;
return id_val;
END;
$$
LANGUAGE plpgsql;
选择funcInsert(666,13,'2014-06-06'
错误:查询没有结果数据的目的地 语境:SQL语句中的PL / pgSQL函数procgtab83(整数,整数,日期)第3行
答案 0 :(得分:6)
create or replace function funcinsert(iacid int, islno int, idate date)
returns int as $$
declare id_val int;
begin
with i as (
insert into gtab83 (acid,slno,orderdte)
values (iacid,islno,idate)
returning orderid
)
select orderid into id_val
from i;
return id_val;
end;
$$ language plpgsql;
它可以像普通的sql
一样简单create or replace function funcinsert(iacid int, islno int, idate date)
returns int as $$
insert into gtab83 (acid,slno,orderdte)
values (iacid,islno,idate)
returning orderid
;
$$ language sql;
答案 1 :(得分:4)
此代码正常运行:
postgres=# create table xx(a int);
CREATE TABLE
postgres=# create or replace function bu(int) returns int as
$$declare x int;
begin
insert into xx values($1) returning a into x;
return x;
end $$ language plpgsql;
CREATE FUNCTION
postgres=# select bu(10);
bu
────
10
(1行)
因为它与你的代码相同,我希望,所以你使用一些非常古老的Postgres。我记得pg中的类似错误,但已经修复了五年多。