Question

我在解释这个问题时遇到了问题，所以如果有人可以对标题或问题进行调整，请执行此操作。

我有一个简单的SQL查询，我正在运行

SELECT orders.customer_no, orders.order_no FROM orders WHERE orders.creation = '01-JAN-14';

导致

customer_no   order_no
----------- ----------
         0    8051729
         2    2809137
         2    3794827
         3    1934678
         3    9237192
         6    3462890
         6    3131378
         6    6267190
         6    2864952
         6    1325645

但我想要的是

customer_no   order_no
----------- ----------
         0    8051729
         2    2809137 3794827
         3    1934678 9237192
         6    3462890 3131378 6267190 2864952 1325645

是否有可能在SQL中直接执行此类操作？

编辑：使用Oracle8i企业版8.1.7.4.0版 - 生产。

Answer 1

我相信你想要：

select orders.customer_no, listagg(orders.order_no, ' ') within group (order by orders.order_no) orders.order_no
  from orders 
  WHERE orders.creation = '01-JAN-14'
  group by orders.customer_no;

在MySQL中你需要GROUP_CONCAT函数，它在Oracle中大致是LISTAGG，根据：

Is there any function in oracle similar to group_concat in mysql?

Answer 2

根据Oracle: Way to aggregate concatenate an ungrouped column in grouped results，您可以尝试以下内容：

WITH j
     AS (SELECT customer_no, order_no
           FROM orders
          WHERE creation = '01-JAN-14')
SELECT   RTRIM (
            EXTRACT (SYS_XMLAGG (XMLELEMENT ("X", order_no || ' ')), '/ROWSET/X/text()').getstringval (),
            ', ')
    FROM j
GROUP BY customer_no;

当LISTAGG和WM_CONCAT不可用时，SQL SELECT将多个行组合在一起

2 个答案: