我正在发送来自Python3脚本的电子邮件（使用smtplib）。到目前为止，我一直在Gmail帐户中收到邮件。但问题是我无法显示CSS样式，尽管是内联的。此外，即使这个简单的消息也无法发送：
title = 'My title'
msg_content = '<h2>{title}: <font color="green">OK</font></h2>\n'.format(title=title)
但是，如果我在{title}之后删除这两个点，它就可以了。如果我删除最后的\ n它将无法再次工作。为什么？如何在Python3中发送这样的一行？
title = 'My title'
msg_content = '<h2>{title}: <span style="color: green">OK</span></h2>'.format(title=title)
修改
import smtplib
msg_header = 'From: Sender Name <sender@server>\n' \
'To: Receiver Name <receiver@server>\n' \
'Cc: Receiver2 Name <receiver2@server>\n' \
'MIME-Version: 1.0\n' \
'Content-type: text/html\n' \
'Subject: Any subject\n'
title = 'My title'
msg_content = '<h2>{title} > <font color="green">OK</font></h2>\n'.format(
title=title)
msg_full = (''.join([msg_header, msg_content])).encode()
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login('sender@server.com', 'senderpassword')
server.sendmail('sender@server.com',
['receiver@server.com', 'receiver@server.com'],
msg_full)
server.quit()
答案 0 :(得分：17)
您的示例的msg_full结果如下所示：
From: Sender Name <sender@server>
To: Receiver Name <receiver@server>
Cc: Receiver2 Name <receiver2@server>
MIME-Version: 1.0
Content-type: text/html
Subject: Any subject
<h2>My title > <font color="green">OK</font></h2>
您的电子邮件格式不符合RFC 2822：
''.join([msg_header, msg_body])，则不会插入此行。因此，您希望传输的正文文本被视为标题。同一封电子邮件的正确版本如下所示：
Content-Type: text/html; charset="us-ascii"
MIME-Version: 1.0
Content-Transfer-Encoding: 7bit
From: Sender Name <sender@server>
To: Receiver Name <receiver@server>
Cc: Receiver2 Name <receiver2@server>
Subject: Any subject
<h2>My title > <font color="green">OK</font></h2>
我强烈建议您使用Python的内置库来构建符合RFC的有效负载。
import smtplib
from email.mime.text import MIMEText
title = 'My title'
msg_content = '<h2>{title} > <font color="green">OK</font></h2>\n'.format(title=title)
message = MIMEText(msg_content, 'html')
message['From'] = 'Sender Name <sender@server>'
message['To'] = 'Receiver Name <receiver@server>'
message['Cc'] = 'Receiver2 Name <receiver2@server>'
message['Subject'] = 'Any subject'
msg_full = message.as_string()
server = smtplib.SMTP('smtp.gmail.com:587')
server.starttls()
server.login('sender@server.com', 'senderpassword')
server.sendmail('sender@server.com',
['receiver@server.com', 'receiver@server.com'],
msg_full)
server.quit()
此外，添加邮件的文本/纯文本版本也是一种很好的形式，这样任何收件人都可以在任何地方阅读它（我禁用了HTML邮件，并且在我的客户端上看不到任何内容）。您可以使用email.mime.text轻松完成此操作：
from email.mime.multipart import MIMEMultipart
message = MIMEMultipart('alternative')
message['From'] = 'Sender Name <sender@server>'
message['To'] = 'Receiver Name <receiver@server>'
message['Cc'] = 'Receiver2 Name <receiver2@server>'
message['Subject'] = 'Any subject'
# Record the MIME types of both parts - text/plain and text/html.
part1 = MIMEText(text, 'plain')
part2 = MIMEText(html, 'html')
# Attach parts into message container.
# According to RFC 2046, the last part of a multipart message, in this case
# the HTML message, is best and preferred.
message.attach(part1)
message.attach(part2)
您的问题缺少用于发送邮件的代码。我强烈怀疑你直接将msg_content作为消息传递给SMTP.sendmail。
然而，SMTP.sendmail按原样发送此字符串，即根据RFC 5321发送邮件的有效负载。此有效内容数据由电子邮件标头和内容组成，邮件顶部有标题（请参阅RFC 2822）。
您的消息“我的标题：我的标题：”并且未在接收端显示。如果你在{title}:之后删除冒号，那么接收器显然不会将结果视为标题等。
对于HTML样式的邮件，请查看https://docs.python.org/2/library/email-examples.html处的示例 - 基本上您必须创建正确的text / html MIME编码邮件才能发送邮件。
答案 1 :(得分：0)
迟到的答案，但有 2021，这是我用 python 发送电子邮件的方法：
import smtplib
from email.mime.text import MIMEText
sender = 'sender@tld'
receivers = ['receiver1@tld', 'receiver2@tld']
body_of_email = 'The body of the email'
msg = MIMEText(body_of_email, 'plain')
# html_body_of_email = '<h1>The html body of the email</h1>'
# msg = MIMEText(html_body_of_email, 'html')
msg['Subject'] = 'The Subject'
msg['From'] = sender
msg['To'] = ','.join(receivers)
s = smtplib.SMTP_SSL(host = 'smtp.gmail.com', port = 465)
s.login(user = 'username', password = 'password')
s.sendmail(sender, receivers, msg.as_string())
s.quit()
在使用 gmail 发送电子邮件之前，请记住在您的 Google 帐户上启用 less secure apps：
Security。Turn on access。