Question

我在android清单中设置了默认操作ACTION_VIEW的活动，我想让活动接收我的应用程序的http，https等url类型的方案。见下面的代码

<activity
        android:name="com.test.ui.LinkLauncherActivity"
        android:label="@string/app_name" 
        android:excludeFromRecents="true"
        android:screenOrientation="portrait"
        android:theme="@android:style/Theme.NoDisplay">
        <intent-filter>
            <action android:name="android.intent.action.VIEW" />
            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <data android:scheme="http" />
            <data android:scheme="https"/>
        </intent-filter>
    </activity>

现在从我的应用程序中我可以选择共享链接，为此我想要打开选择意图与选定的应用程序应该只在选择对话框中列出的排除我自己的应用程序。
目前，当我通过操作查询包管理器时（ACTION_VIEW）它将返回我的应用程序列表找到我的包名我只是忽略它并打开选择意图但是它仍然显示我在自定义共享意图对话框中的应用程序。
是否因为我在上面的代码中将类别定义为清单中的默认值？

让我们分享自定义意图代码

Uri uriUrl = Uri.parse(mlm.getHitUrl());
//get package manager
PackageManager pm = getPackageManager();

Intent viewIntent = new Intent(Intent.ACTION_VIEW,uriUrl);

List<ResolveInfo> resInfo = pm.queryIntentActivities(viewIntent, 0);

List<LabeledIntent> intentList = new ArrayList<LabeledIntent>(resInfo.size() - 1); 

for (int i = 0; i < resInfo.size(); i++) 
{
    // Extract the label, append it, and repackage it in a LabeledIntent 
    ResolveInfo ri = resInfo.get(i);

    String packageName = ri.activityInfo.packageName;

    Log.d(getTag(),String.format("PackageName : %2s",packageName));

    if (!TextUtils.equals(packageName,"my application packageName")) {

        Intent intent = new Intent(Intent.ACTION_VIEW,uriUrl);
        intent.setPackage(packageName);
        intentList.add(new LabeledIntent(intent, packageName, ri.loadLabel(pm), ri.icon));
    }
}

// convert intentList to array 
LabeledIntent[] extraIntents = intentList.toArray( new LabeledIntent[ intentList.size() ]);

Intent openInChooser = Intent.createChooser(viewIntent, getResources().getString(R.string.intent_title_open_link));

openInChooser.putExtra(Intent.EXTRA_INITIAL_INTENTS, extraIntents);

openInChooser.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);

startActivity(openInChooser);

上面的代码仍然向我展示了我在意图对话框中的应用程序。

Answer 1

试试这段代码。

Intent intent = new Intent();

    intent.setAction(android.content.Intent.ACTION_VIEW);

    MimeTypeMap mime = MimeTypeMap.getSingleton();

    String ext = file.getName().substring(file.getName().indexOf(".")+1);

    String type = mime.getMimeTypeFromExtension(ext);

    intent.setDataAndType(Uri.fromFile(file),type);

    PackageManager packageManager = activity.getPackageManager();

    List<ResolveInfo> activities = packageManager.queryIntentActivities(intent, 0);

    String packageNameOfAppToHide = "com.test.app";

    ArrayList<Intent> targetIntents = new ArrayList<Intent>();

    for (ResolveInfo currentInfo : activities) {

            String packageName = currentInfo.activityInfo.packageName;

        if (packageNameToHide.equals(packageName)) {

            Intent targetIntent = new Intent(android.content.Intent.ACTION_VIEW);

            targetIntent.setDataAndType(Uri.fromFile(file),type);
            targetIntent.setPackage(packageName);
            targetIntents.add(targetIntent);
        }
    }
    if(targetIntents.size()>0) {

        Intent chooserIntent = Intent.createChooser(targetIntents.remove(0), "Open file with");

        chooserIntent.putExtra(Intent.EXTRA_INITIAL_INTENTS, targetIntents.toArray(new Parcelable[] {}));

        activity.startActivity(chooserIntent);
    }
    else
        Toast.makeText(this, "No app found", Toast.LENGTH_SHORT).show();

com.test.app是您的应用程序的软件包名称。

自定义选择意图并排除我自己的活动

1 个答案: