好的,我在尝试学习XmlSerializer时遇到了一些问题。我已经遵循了所有建议的步骤,但我的程序没有返回任何内容,或者返回null。我创建了一个XML文件,如下所示:
<?xml version='1.0' encoding='UTF-8' ?>
<WeeklyJobs>
<DailyJobs Date = "02/03/2012"/>
<DailyJobs Date = "02/04/2012" TotalJobs = "2">
<Jobs>
<Job JobName = "Job Name" Description = "Description"/>
<Job JobName = "Job Name" Description = "Description"/>
</Jobs>
</DailyJobs>
<DailyJobs Date = "02/05/2012" TotalJobs = "1">
<Jobs>
<Job JobName = "Job Name" Description = "Description"/>
</Jobs>
</DailyJobs>
<DailyJobs Date = "02/06/2012" TotalJobs = "2">
<Jobs>
<Job JobName = "Job Name" Description = "Description"/>
<Job JobName = "Job Name" Description = "Description"/>
</Jobs>
</DailyJobs>
<DailyJobs Date = "02/07/2012"/>
<DailyJobs Date = "02/08/2012" TotalJobs = "2">
<Jobs>
<Job JobName = "Job Name" Description = "Description"/>
<Job JobName = "Job Name" Description = "Description"/>
</Jobs>
</DailyJobs>
</WeeklyJobs>
然后我使用xsd.exe生成.xsd文件:
<?xml version="1.0" encoding="utf-8"?>
<xs:schema id="WeeklyJobs" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
<xs:element name="WeeklyJobs" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
<xs:complexType>
<xs:choice minOccurs="0" maxOccurs="unbounded">
<xs:element name="DailyJobs">
<xs:complexType>
<xs:sequence>
<xs:element name="Jobs" minOccurs="0" maxOccurs="unbounded">
<xs:complexType>
<xs:sequence>
<xs:element name="Job" minOccurs="0" maxOccurs="unbounded">
<xs:complexType>
<xs:attribute name="JobName" type="xs:string" />
<xs:attribute name="Description" type="xs:string" />
</xs:complexType>
</xs:element>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:sequence>
<xs:attribute name="Date" type="xs:string" />
<xs:attribute name="TotalJobs" type="xs:string" />
</xs:complexType>
</xs:element>
</xs:choice>
</xs:complexType>
</xs:element>
</xs:schema>
创建架构后,我再次使用xsd.exe为我自动生成类:
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
public partial class WeeklyJobs
{
private WeeklyJobsDailyJobs[] itemsField;
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute("DailyJobs", Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
public WeeklyJobsDailyJobs[] Items
{
get
{
return this.itemsField;
}
set
{
this.itemsField = value;
}
}
}
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class WeeklyJobsDailyJobs
{
private WeeklyJobsDailyJobsJobsJob[][] jobsField;
private string dateField;
private string totalJobsField;
/// <remarks/>
[System.Xml.Serialization.XmlArrayAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
[System.Xml.Serialization.XmlArrayItemAttribute("Job", typeof(WeeklyJobsDailyJobsJobsJob), Form = System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable = false)]
public WeeklyJobsDailyJobsJobsJob[][] Jobs
{
get
{
return this.jobsField;
}
set
{
this.jobsField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string Date
{
get
{
return this.dateField;
}
set
{
this.dateField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string TotalJobs
{
get
{
return this.totalJobsField;
}
set
{
this.totalJobsField = value;
}
}
}
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class WeeklyJobsDailyJobsJobsJob
{
private string jobNameField;
private string descriptionField;
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string JobName
{
get
{
return this.jobNameField;
}
set
{
this.jobNameField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string Description
{
get
{
return this.descriptionField;
}
set
{
this.descriptionField = value;
}
}
}
在此之后,我将.CS文件添加到我的项目中,并创建了一个带有TextBox的简单winform,以便在我对一些xml进行反序列化后显示一些数据。就像我说程序启动一样,TextBox中没有显示任何内容,也没有抛出异常。这是我的winform:
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
public string getExample()
{
XmlSerializer serializer = new XmlSerializer(typeof(WeeklyJobs));
WeeklyJobs jobs;
string xml = @"<?xml version = ""1.0""?>"
+ @"<WeeklyJobs>"
+ @"<DailyJobs Date = ""02/03/2012""/>"
+ @"<DailyJobs Date = ""02/04/2012"" TotalJobs = ""2"">"
+ @"<Jobs>"
+ @"<Job JobName = ""Job Name"" Description = ""Description""/>"
+ @"<Job JobName = ""Job Name"" Description = ""Description""/>"
+ @"</Jobs>"
+ @"</DailyJobs>"
+ @"</WeeklyJobs>";
// Create an XmlTextReader
using (XmlReader reader = XmlReader.Create(new StringReader(xml)))
{
jobs = (WeeklyJobs)serializer.Deserialize(reader);
}
return jobs.Items[0].Date;
}
private void Form1_Load(object sender, EventArgs e)
{
textBox1.Text = getExample();
}
}
我有更简单的xml示例可以工作但是我第二次尝试为我的xml添加一些复杂性我失败了。我必须弄清楚如何使用我在这里的xml。我很感激帮助!谢谢大家!
答案 0 :(得分:3)
好的,第一个问题是XmlSerializer构造函数正在引发一个未处理的异常,但这种情况在某种程度上被吞噬了。这解释了文本框为空的原因。我将调试器设置为中断所有CLR异常,并发现构造函数抛出InvalidOperationException - 显然是在代码生成过程中:
无法生成临时类(result = 1)。
错误CS0030:无法转换类型&#39; DeleteMe.WeeklyJobsDailyJobsJobsJob []&#39; to&#39; DeleteMe.WeeklyJobsDailyJobsJobsJob&#39;
错误CS0029:无法隐式转换类型&#39; DeleteMe.WeeklyJobsDailyJobsJobsJob&#39; to&#39; DeleteMe.WeeklyJobsDailyJobsJobsJob []&#39;
(构造函数也抛出一个FileNotFound异常,但它也会处理它,所以你可以忽略它。)
似乎问题是锯齿状数组 - 你是否将1维数组更改为锯齿状数组?当然,错误消息指出了我的方向,但我也从未在xsd生成的代码中看到过锯齿状数组,因此看起来很可疑。我将WeeklyJobsDailyJobsJobsJob[][]
的两次更改更改为WeeklyJobsDailyJobsJobsJob[]
,应用程序运行正常。
另外,您应该使用DateTime
作为日期,但XML序列化程序不支持可变日期格式(请参阅https://stackoverflow.com/a/1118855/385844)。如果您无法控制源代码,那么在将字符串存储到数据库或任何地方之前,最好将字符串转换为日期。