Question

这是我的代码：

$convertTitle = $this->art->catList(); // gets an array which has other arrays as its values
    foreach($convertTitle as $cT){ // cycle through the smaller arrays
        if(in_array($cat, $cT)){ // if "xx" is found in a smaller array
            $data['title'] = $cT['full']; // set the $title to the full form corresponding to the abbreviated xx ($cat) 
        }
        if(!in_array($cat, $cT)){ 
            $data['title'] = "Sorry, an error occurred."; // if it's not found, choose an alternate title 
            $data['error'] = 1; // throw the error
        } 
    }

为了调试，我一直在打印in_array($cat, $cT)，当我期望它时，它输出1.当我期望它时，它也输出0。所以它似乎在起作用。我甚至可以print($data['title']);并显示正确的标题！但无论in_array()是输出1还是0，我的第二个if语句总是覆盖第一个，而I $错误总是出现1.什么给出？

我尝试过的一些解决方案：

if(!in_array($cat, $cT)... 
if(in_array($cat, $cT) == false/0/null)...
else...

我真的不知道为什么当我想要的时候标题位于变量中时它没有输出正确的标题！

编辑：这是print_r($convertTitle);

Array ( [0] => Array ( [handle] => dr [full] => Drawings ) [1] => Array ( [handle] => f [full] => Films & Stills ) [2] => Array ( [handle] => pa [full] => Paintings ) [3] => Array ( [handle] => ph [full] => Photography ) [4] => Array ( [handle] => po [full] => Portraits ) )

Answer 1

为什么不只是else？

if (in_array()) {
   ...
} else {
   ...
}

当条件是彼此的布尔对立时，有两个单独的if（）测试基本没有意义。

另外，请记住，您的foreach()会迭代许多项目。对于数组中没有的 EVERY 项，您将$error设置为TRUE。但是当你做匹配时，你不会将其重置为FALSE。所以

array item #1 -> not found, so error => true
array item #2 -> not found, so error => true
array item #3 -> found! -> don't change error, it's still true
array item ....
etc...

Answer 2

您在foreach循环的每次迭代中都会覆盖您的值，因此最终会得到title的最后一个值的结果，并且您的error将保留一次它已经确定。

除此之外，你应该写一下：

if (in_array()) {

} else {

}

Answer 3

感谢您的回答！我忘记了即使在找到正确的条目后，循环也会反复运行。为了将来参考，以下是有效的代码：

$convertTitle = $this->art->catList(); 
    foreach($convertTitle as $cT){ 
        if(in_array($cat, $cT)){ 
            $data['title'] = $cT['full']; 
            $data['error'] = 0; 
            break; 
        }
        else{ 
            $data['title'] = "Sorry, an error occurred."; 
            $data['error'] = 1; 
        } 
    }

PHP in_array（）不会传递if ... else

3 个答案: