Question

我想在cost，amt列中添加值 - 如果在同一日期有同一个人flag的{{1}} 1和2。请帮忙。谢谢。专栏是：

id

输出应该是：

id  date    cost    amt flag
455 05/25/2013  150 110 1
455 05/25/2013  20  45  2
456 08/17/2013  140 60  1
456 08/17/2013  15  20  2
457 09/28/2013  135 10  1
457 09/28/2013  8   40  2
458 11/09/2013  10  30  1

Answer 1

只是为了多样性，请查看我的解决方案。它使用over (partition by )进行计算，使用distinct过滤掉重复项。

select distinct o.ID, o.Date,
  SUM(o.COST) OVER(PARTITION BY o.ID, o.Date) as cost
 ,SUM(o.AMT) OVER(PARTITION BY o.ID, o.Date) as amt
 ,MIN(FLAG) OVER(PARTITION BY o.ID, o.Date) as flag
from orders o
order by o.ID, o.Date

SqlFiddle proof

受this article启发。

Answer 2

不确定你想用旗帜做什么，但你需要GROUP BY喜欢：

SELECT id, date, SUM(cost), Sum(amt), 1 as flag
FROM yourTable
GROUP BY id,date

Answer 3

SELECT ID, DATE , SUM(COST), SUM(AMT), MIN(Flag) FROM TABLE GROUP BY ID, DATE

Answer 4

如果您需要在同一日期对同一个ID进行标记1和2，那么这应该有效：

SELECT id, date, SUM(cost), SUM(amt) , flag
FROM yourtable a
WHERE flag=1 
AND EXISTS (SELECT 1 FROM yourtable b WHERE a.id=b.id AND b.flag=2 AND a.date=b.date)
GROUP BY id, date, flag

对相同日期和ID的列中的值求和

4 个答案: