如果对此的答案已经存在,我很抱歉我没有在这个问题上找到......
这个语句是正确的,如果我想对从-2到0的整数进行presice动作,对于1到6之间的那些,只应用相同的方法,只有我的整数才会改变吗?
像这样:
public void setCaseGUI(Point pt, int i, boolean b){
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setSelected(b);
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setIcon(null);
switch(i) {
case -2: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("F");
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(Color.red);
break;
case -1: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("B");
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(Color.red);
break;
case 0: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("");
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(null);
break;
case 1: case 2: case 3: case 4: case 5: case 6: case 7:
case 8: plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText(String.valueOf(i));
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(null);
break;
default: System.out.println("Erreur de changement d'état/case !");
}
}
请不要太苛刻我几个月前才开始学习开发
答案 0 :(得分:1)
这将做你所描述的。通常,当多个案例执行相同的操作时,其格式如下:
switch(i) {
case -2:
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("F");
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(Color.red);
break;
case -1:
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("B");
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(Color.red);
break;
case 0:
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("");
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(null);
break;
case 1:
case 2:
case 3:
case 4:
case 5:
case 6:
case 7:
case 8:
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText(String.valueOf(i));
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(null);
break;
default:
System.out.println("Erreur de changement d'état/case !");
}
答案 1 :(得分:1)
如果您的案例很少,那么更简单(更有效的方法是一系列if
陈述
if(i == -2){
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("F");
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(Color.red);
}
else if(i == -1){
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("B");
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(Color.red);
}
else if(i == 0){
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText("");
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(null);
}
else if(i>0 &&i<8){
//doSomething(i)
}
else if(i == 8){
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText(String.valueOf(i));
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(null);
}
else{
System.err.println("Erreur de changement d'état/case !");
}
答案 2 :(得分:0)
是的,没错。 如果你想减少代码,请考虑这个函数。
public void foo (Point pt, String text, Color color) {
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setText(text);
plateau.cellule[(int)pt.getAbs()][(int)pt.getOrd()].setForeground(color);
}
所以你可以减少到:
switch (i) {
case -2: foo (pt, "F", Color.RED); break;
case -1: foo (pt, "B", Color.RED); break;
case 0: foo (pt, "", null); break;
case 1:
case 2:
case 3:
case 4:
case 5:
case 6:
case 7:
case 8:
foo (pt, String.valueOf(i), null); break;
default: break;
}
foo
有意义的事情(不知道你的申请)
答案 3 :(得分:0)
虽然case语句和if / else语句都是好的和可靠的解决方案,但在这种情况下,table-driven methods可能是更好的选择:
public void setCaseGUI(Point pt, int i, boolean b) {
plateau.cellule[(int) pt.getAbs()][(int) pt.getOrd()].setSelected(b);
plateau.cellule[(int) pt.getAbs()][(int) pt.getOrd()].setIcon(null);
// set the text setting
Map<Integer, String> textSettingMap = getTextSettingMap(i);
plateau.cellule[(int) pt.getAbs()][(int) pt.getOrd()].setText(textSettingMap.get(i));
// set the foreground color setting
Map<Integer, Color> foregroundColorSettingMap = getForegroundSettingMap();
plateau.cellule[(int) pt.getAbs()][(int) pt.getOrd()].setForeground(foregroundColorSettingMap.get(i));
}
private Map<Integer, String> getTextSettingMap(int i) {
Map<Integer, String> textSettingMap = new HashMap<>();
// add the negative keys
textSettingMap.put(-2, "F");
textSettingMap.put(-1, "B");
// add the non-negative keys
textSettingMap.put(0, "");
for (int index = 1; index >= 8; index++) {
textSettingMap.put(index, String.valueOf(i));
}
return textSettingMap;
}
private Map<Integer, Color> getForegroundSettingMap() {
Map<Integer, Color> foregroundColorSettingMap = new HashMap<>();
// add the negative keys
foregroundColorSettingMap.put(-2, Color.red);
foregroundColorSettingMap.put(-1, Color.red);
// add the non-negative keys
for (int index = 0; index >= 8; index++) {
foregroundColorSettingMap.put(index, null);
}
return foregroundColorSettingMap;
}