Question

有没有更好的方法来解决这个问题。我的mixin包含开始变得重复，并且不知道是否有更好的方法来执行此操作：

@mixin button-type($name, $bgColor, $borderColor, $color, $hoverBg, $hoverColor) {
 .btn-#{$name} {
    background-color : $bgColor;
    border-color     : $borderColor;
    color            : $color;

    &:hover {
        background-color : $hoverBg;
        border-color     : $borderColor;
        box-shadow       : 0 0 5px rgba(0, 0, 0, .5);
        color            : $hoverColor;
    }
  }
}

@include button-type('warning', #fff, $dark-blue, $black, $dark-blue, #fff);
@include button-type('primary', #fff, $dark-blue, $black, $dark-blue, #fff);
@include button-type('active', #fff, $dark-blue, $black, $dark-blue, #fff);

Answer 1

你可以制作另一个mixin，用你的mixin调用所需属性的硬编码值：

@mixin dark-blue-button-type($name) {
    @include button-type($name, #fff, $dark-blue, $black, $dark-blue, #fff);
}

所以称之为：

@include dark-blue-button-type('warning');
@include dark-blue-button-type('primary');
@include dark-blue-button-type('active');

Sass mixin变得多余

1 个答案: