Question

在我的应用中，我以特定格式从我的数据库中检索日期。（由PHP生成）

我想在我的Android应用中针对这种情况显示特定输出：

来自数据库的输入格式： 2014-05-30 17:50:50

我希望能够在TexView中显示这种格式：

如果日期是指今天，我想显示这种格式：

今天 - 17h50

如果日期是指昨天，我会显示以下格式：

昨天 - 17h50

其他日子：

6月5日 - 17日50日

我该怎么做？

[UPDATE]

String dateDebut = annonce.getDate_debut();

            SimpleDateFormat inDF = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); // inputFormat
            SimpleDateFormat TodayDF = new SimpleDateFormat("HH'h'mm"); //OutputFormat For today and yesterday
            SimpleDateFormat FullDF = new SimpleDateFormat("dd MMM - HH'h'mm"); //Outputformat long

            Date inDate = null;
            try {
                inDate = inDF.parse(dateDebut);
            } catch (ParseException e) {
                // TODO Auto-generated catch block
                e.printStackTrace();
            }
            //calendar for inputday
            Calendar inCal = new GregorianCalendar();
            inCal.setTime(inDate);
            //startOfToday
            Calendar cStartOfDate = new GregorianCalendar();
            cStartOfDate.set(Calendar.HOUR, 0);
            cStartOfDate.set(Calendar.MINUTE, 0);
            cStartOfDate.set(Calendar.SECOND, 0);
            cStartOfDate.set(Calendar.MILLISECOND, 0);
            //endOfToday    
            Calendar cEndOfDate = new GregorianCalendar();
            cEndOfDate.set(Calendar.HOUR, 23);
            cEndOfDate.set(Calendar.MINUTE, 59);
            cEndOfDate.set(Calendar.SECOND, 59);

             //startOfYesterday
            Calendar cStartOfYesterday = new GregorianCalendar();
            cStartOfYesterday.set(Calendar.HOUR, 0);
            cStartOfYesterday.set(Calendar.MINUTE, 0);
            cStartOfYesterday.set(Calendar.SECOND, 0);
            cStartOfYesterday.set(Calendar.MILLISECOND, 0);

             //endOfYesterday
            Calendar cEndOfYesterday = new GregorianCalendar();
            cEndOfYesterday.set(Calendar.HOUR, 23);
            cEndOfYesterday.set(Calendar.MINUTE, 59);
            cEndOfYesterday.set(Calendar.SECOND, 59);

            if (cStartOfDate.before(inCal) && cEndOfDate.after(inCal)){
              System.out.println("Aujourd'hui - "+TodayDF.format(inDate));
              viewHolder.dateDebut.setText("Aujourd'hui - "+TodayDF.format(inDate));
            } else if (cStartOfYesterday.before(inCal) && cEndOfYesterday.after(inCal)){
              System.out.println("Hier - "+TodayDF.format(inDate));
              viewHolder.dateDebut.setText("Hier - "+TodayDF.format(inDate));
            }  else {
              System.out.println(FullDF.format(inDate));
              viewHolder.dateDebut.setText(FullDF.format(inDate));
            }

Answer 1

试用此代码：

  DateFormat inDF = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss"); // inputFormat
    DateFormat TodayDF = new SimpleDateFormat("HH'h'mm"); //OutputFormat For today and yesterday
    DateFormat FullDF = new SimpleDateFormat("dd MMM - HH'h'mm"); //Outputformat long

    Date inDate = inDF.parse("2014-06-05 17:50:50");
    //calendar for inputday
    Calendar inCal = new GregorianCalendar();
    inCal.setTime(inDate);
    //startOfToday
    Calendar cStartOfDate = new GregorianCalendar();
    cStartOfDate.set(Calendar.HOUR_OF_DAY, 0);
    cStartOfDate.set(Calendar.MINUTE, 0);
    cStartOfDate.set(Calendar.SECOND, 0);
    cStartOfDate.set(Calendar.MILLISECOND, 0);
    //endOfToday    
    Calendar cEndOfDate = new GregorianCalendar();
    cEndOfDate.set(Calendar.HOUR_OF_DAY, 23);
    cEndOfDate.set(Calendar.MINUTE, 59);
    cEndOfDate.set(Calendar.SECOND, 59);

     //startOfYesterday
    Calendar cStartOfYesterday = new GregorianCalendar();
    cStartOfYesterday.set(Calendar.HOUR_OF_DAY, 0);
    cStartOfYesterday.set(Calendar.MINUTE, 0);
    cStartOfYesterday.set(Calendar.SECOND, 0);
    cStartOfYesterday.set(Calendar.MILLISECOND, 0);

     //endOfYesterday
    Calendar cEndOfYesterday = new GregorianCalendar();
    cEndOfYesterday.set(Calendar.HOUR_OF_DAY, 23);
    cEndOfYesterday.set(Calendar.MINUTE, 59);
    cEndOfYesterday.set(Calendar.SECOND, 59);

    if (cStartOfDate.before(inCal) && cEndOfDate.after(inCal)){
      System.out.println("Today "+TodayDF.format(inDate));
    } else if (cStartOfYesterday.before(inCal) && cEndOfYesterday.after(inCal)){
      System.out.println("Yesterday"+TodayDF.format(inDate));
    }  else {

      System.out.println(FullDF.format(inDate));
    }

Answer 2

首先将从数据库获取的日期转换为日历实例
可以使用日历实例
对于其他格式，请使用以下：

代码：

Calendar cal = Calendar.getInstance();
new SimpleDateFormat("dd MMMM - HH").format(cal.getTime())+ 
"h" + new SimpleDateFormat("mm").format(cal.getTime())

Answer 3

这是一个完整的解决方案。我没试过，但它应该有效。

NB：请注意输入限制：例如，如果日期是01/01/2015，我不确定它是否会起作用。 我让你测试一下。

private boolean checkSameDate(Calendar cal1, Calendar cal2) {
        if ((cal1.get(Calendar.YEAR) == cal2.get(Calendar.YEAR)) 
                && (cal1.get(Calendar.DAY_OF_YEAR) == cal2.get(Calendar.DAY_OF_YEAR))) {
            return true;
        }
        return false;
}

private void checkDate(Date date) {
        Calendar cal = new GregorianCalendar();
        cal.setTime(new Date());
        Calendar cal2 = new GregorianCalendar();
        cal2.setTime(date);
        cal.add(Calendar.DAY_OF_YEAR, 1);
        if (checkSameDate(cal, cal2)) {
            // Your input date is tomorrow.
        } else {
            cal.add(Calendar.DAY_OF_YEAR, -2);
            if (checkSameDate(cal, cal2)) {
                // Your input date is yesterday.
            } else {
                DateFormat sdf = new SimpleDateFormat("dd MMMM - HH:mm");
                System.out.println(sdf.format(date));
            }
        }
}

修改

抱歉，我认为今天是01/01 / YYYY时，31/12 / YYYY-1的日期不适用。也许您可以使用这种解决方案修复此代码：Check if one date is exactly 24 hours or more after another

对于SimpleDateFormat，如果这是您需要的格式，我可以在此处https://ideone.com/dsxKN9查看。

修改2

我只是看到你想要今天而不是明天 :)。我的错！我会尝试解决此问题，但如果您理解逻辑，那么您就可以做到。

Answer 4

您可以使用此功能：

public static String convertDate(String stringDate, String oldFormat) throws ParseException {        
        SimpleDateFormat sdf = new SimpleDateFormat(oldFormat);
        Date date = sdf.parse(stringDate);
        double daysAgo = (System.currentTimeMillis() - date.getTime()) / (24 * 60 * 60 * 1000d);
        System.out.println(daysAgo);
        String newFormat;
        if (daysAgo<=0){
            newFormat="'Today -' HH'h'mm";
        }
        else if (daysAgo>=0 && daysAgo<=1){
            newFormat="'Yesterday -' HH'h'mm";
        }
        else {
            newFormat="d MMMM '-' HH'h'mm";
        }
        sdf.applyPattern(newFormat);
        return sdf.format(date);
    }

用法是：

String newDate = convertDate("2014-06-03 17:50:50", "yyyy-MM-dd HH:mm:ss");

Java：如何解析日期格式以显示特定的输出格式？

4 个答案: