Question

我为django项目构建了一个AbstractUser模型的扩展，我有几个应该自动填充的字段，一个唯一的字符串，一个创建和修改的时间戳。

我使用包django-model-utils中的字段来创建和修改工作，并且我已根据相同的原则为代码构建了自己的自定义字段。

django管理员似乎无法找到这些字段。

除了django-admin之外，这些字段似乎无处不在。

以下是代码的准系统：

models.py 来自django.contrib.auth.models导入AbstractUser

from model_utils import Choices
from model_utils.fields import AutoCreatedField, AutoLastModifiedField

from .fields import CoombaCodeField



class CoombaUser(AbstractUser):
    # class CoombaUser(models.Model):
    # Timestamp. Created timestamp is suppled by AbstractUser, as date_joined
    modified = AutoLastModifiedField(_('modified'))

    # string identifer, used in referrals
    coomba_code = CoombaCodeField()

fields.py

from django.db import models, OperationalError

from core.keyGenerators import ShortKeyGenerator, KeyGenerator

from .settings import COOMBA_CODE_COUNTER_KEY, COOMBA_CODE_COUNTER_MINIMUM

# Impossible to call code accessing databases before databases are created.
# Code below moves database call to first use.

coomba_code_generator = None


def get_key():
    global coomba_code_generator
    if(coomba_code_generator is None):
        coomba_code_generator = ShortKeyGenerator(
            charset=KeyGenerator.CHARSET_FULL,
            counter_key=COOMBA_CODE_COUNTER_KEY,
            smallest_allowed_value=COOMBA_CODE_COUNTER_MINIMUM
        )
    key = coomba_code_generator.get_key()
    return key


class CoombaCodeField(models.CharField):

    def __init__(self, *args, **kwargs):
        kwargs.setdefault('editable', False)
        kwargs.setdefault('default', get_key)
        kwargs.setdefault('max_length', 30)
        super(CoombaCodeField, self).__init__(*args, **kwargs)

admin.py 来自django.contrib import admin

from .models import CoombaUser


def full_name(user):
    return (user.first_name + " " + user.last_name)


class CoombaUserAdmin(admin.ModelAdmin):

    list_display = ("email", full_name, "date_joined")
    fieldsets = (
        ("CoombaUser", {
            'fields': (
                "email",
                ("first_name", "last_name"),
                "nickname",
                "coomba_code",
                "social_security_number",
                "gender",
                "date_of_birth",
                "account_status",
                "last_login",
            ),
        }),
    )

admin.site.register(CoombaUser, CoombaUserAdmin)

错误：

Environment:


Request Method: GET
Request URL: http://127.0.0.1:8000/admin/coombaUsers/coombauser/1/

Django Version: 1.6.5
Python Version: 2.7.6
Installed Applications:
('django.contrib.auth',
 'django.contrib.contenttypes',
 'django.contrib.sessions',
 'django.contrib.sites',
 'django.contrib.messages',
 'django.contrib.staticfiles',
 'django.contrib.admin',
 'core',
 'coombaUsers',
 'allauth',
 'allauth.account',
 'allauth.socialaccount',
 'allauth.socialaccount.providers.google',
 'allauth.socialaccount.providers.linkedin',
 'djangular',
 'localflavor',
 'parsley',
 'crispy_forms',
 'south',
 'django_coverage')
Installed Middleware:
('django.middleware.common.CommonMiddleware',
 'django.contrib.sessions.middleware.SessionMiddleware',
 'django.middleware.locale.LocaleMiddleware',
 'django.middleware.csrf.CsrfViewMiddleware',
 'django.contrib.auth.middleware.AuthenticationMiddleware',
 'django.contrib.messages.middleware.MessageMiddleware',
 'django.middleware.clickjacking.XFrameOptionsMiddleware')


Traceback:
File "C:\Users\Sverker\.virtualenvs\coomba\lib\site-packages\django\core\handlers\base.py" in get_response
  112.                     response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "C:\Users\Sverker\.virtualenvs\coomba\lib\site-packages\django\contrib\admin\options.py" in wrapper
  432.                 return self.admin_site.admin_view(view)(*args, **kwargs)
File "C:\Users\Sverker\.virtualenvs\coomba\lib\site-packages\django\utils\decorators.py" in _wrapped_view
  99.                     response = view_func(request, *args, **kwargs)
File "C:\Users\Sverker\.virtualenvs\coomba\lib\site-packages\django\views\decorators\cache.py" in _wrapped_view_func
  52.         response = view_func(request, *args, **kwargs)
File "C:\Users\Sverker\.virtualenvs\coomba\lib\site-packages\django\contrib\admin\sites.py" in inner
  198.             return view(request, *args, **kwargs)
File "C:\Users\Sverker\.virtualenvs\coomba\lib\site-packages\django\utils\decorators.py" in _wrapper
  29.             return bound_func(*args, **kwargs)
File "C:\Users\Sverker\.virtualenvs\coomba\lib\site-packages\django\utils\decorators.py" in _wrapped_view
  99.                     response = view_func(request, *args, **kwargs)
File "C:\Users\Sverker\.virtualenvs\coomba\lib\site-packages\django\utils\decorators.py" in bound_func
  25.                 return func(self, *args2, **kwargs2)
File "C:\Users\Sverker\.virtualenvs\coomba\lib\site-packages\django\db\transaction.py" in inner
  371.                 return func(*args, **kwargs)
File "C:\Users\Sverker\.virtualenvs\coomba\lib\site-packages\django\contrib\admin\options.py" in change_view
  1206.         ModelForm = self.get_form(request, obj)
File "C:\Users\Sverker\.virtualenvs\coomba\lib\site-packages\django\contrib\admin\options.py" in get_form
  531.                              % (e, self.__class__.__name__))

Exception Type: FieldError at /admin/coombaUsers/coombauser/1/
Exception Value: Unknown field(s) (coomba_code) specified for CoombaUser. Check fields/fieldsets/exclude attributes of class CoombaUserAdmin.

Answer 1

不确定这是否会解决您的错误，但为什么要定义：

def full_name(user):
    ...

以外：

class CoombaUserAdmin(admin.ModelAdmin):
    ....

如何将用户对象传递给full_name（）

我会这样做：

class CoombaUserAdmin(admin.ModelAdmin):
    list_display = ("email", "full_name", "date_joined")

    def full_name(self, obj):
        return u'%s %s' % (obj.first_name, obj.last_name)
    full_name.short_description = "Full Name"

请参阅https://docs.djangoproject.com/en/dev/ref/contrib/admin/#django.contrib.admin.ModelAdmin.list_display

doc：

中的示例

class PersonAdmin(admin.ModelAdmin):
    list_display = ('upper_case_name',)

    def upper_case_name(self, obj):
        return ("%s %s" % (obj.first_name, obj.last_name)).upper()
    upper_case_name.short_description = 'Name'

Django管理员无法找到models.CharField的子类

1 个答案: