Question

我正在努力在自己的函数中包含数据库连接。为了简单起见，一切都在一个文件中。我想我需要通过connect函数传递$ db，但我不知道如何将它声明为空对象。我尝试使db成为一个类，然后将db_connect的内容放入__construct并使用$ db = new db;但那也不起作用。

function db_connect(){
try {
    $db = new PDO('mysql:host=xxx.xxx.com;dbname=xxx;charset=utf8', 'xxx', 'xxx');
    $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
}
catch(PDOException $e)
{
    echo $e->getMessage();
}
}

function getTeamCount($leagueId){
    db_connect();
    $teamCount = $db->prepare('SELECT ...................');
    $teamCount->execute();
    $teamCountResult = $teamCount->fetchAll(PDO::FETCH_ASSOC);
    $teamsCounted = $teamCount->rowCount();
......
......
}

Answer 1

function db_connect(){
    try {
        $db = new PDO('mysql:host=xxx.xxx.com;dbname=xxx;charset=utf8', 'xxx', 'xxx');
        $db->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    }
    catch(PDOException $e)
    {
        echo $e->getMessage();
    }
    return $db; //here!
}

function getTeamCount($leagueId){
    $db = db_connect();
    ...
}

PHP不能将数据库连接包含到函数中

1 个答案: