Question

我从一个网站上获得了这个游戏演示，并注意到了这段代码：

if(nx == food.x && ny == food.y) {
    var tail = {x: nx, y: ny};
    score++;
    create_food();
} else {
    var tail = snake_array.pop(); 
    tail.x = nx; tail.y = ny;
}

snake_array.unshift(tail); //how is tail used here?

我没有发现'tail'变量的任何其他声明，所以这是怎么回事？我对这个编程领域（web开发/脚本语言）很陌生，所以我不确定是否允许这样做。

完整代码：

$(document).ready(function(){
    var canvas = $("#canvas")[0];
    var ctx = canvas.getContext("2d");
    var w = $("#canvas").width();
    var h = $("#canvas").height();

    var cw = 10;
    var d;
    var food;
    var score;

    var snake_array; 

    function init() {
        d = "right"; 
        create_snake();
        create_food(); 
        score = 0;

        if(typeof game_loop != "undefined") clearInterval(game_loop);
        game_loop = setInterval(paint, 60);
    }
    init();

    function create_snake() {
        var length = 5; 
        snake_array = []; 
        for(var i = length-1; i>=0; i--) {
            snake_array.push({x: i, y:0});
        }
    }

    function create_food() {
        food = {
            x: Math.round(Math.random()*(w-cw)/cw), 
            y: Math.round(Math.random()*(h-cw)/cw), 
        };
    }                

    function paint() {
        ctx.fillStyle = "white";
        ctx.fillRect(0, 0, w, h);
        ctx.strokeStyle = "black";
        ctx.strokeRect(0, 0, w, h);

        var nx = snake_array[0].x;
        var ny = snake_array[0].y;

if(d == "right") nx++;
        else if(d == "left") nx--;
        else if(d == "up") ny--;
        else if(d == "down") ny++;

        if(nx == -1 || nx == w/cw || ny == -1 || ny == h/cw || check_collision(nx, ny, snake_array)) {
            init();
            return;
        }

        /* @@@@@@@@@ This is where it is happening @@@@@@@@@ */
        if(nx == food.x && ny == food.y) {
            var tail = {x: nx, y: ny};
            score++;
            create_food();
        } else {
            var tail = snake_array.pop(); 
            tail.x = nx; tail.y = ny;
        }

        snake_array.unshift(tail);

        for(var i = 0; i < snake_array.length; i++) {
            var c = snake_array[i];
            paint_cell(c.x, c.y);
        }

        paint_cell(food.x, food.y);
        var score_text = "Score: " + score;
        ctx.fillText(score_text, 5, h-5);
    }

    function paint_cell(x, y) {
        ctx.fillStyle = "blue";
        ctx.fillRect(x*cw, y*cw, cw, cw);
        ctx.strokeStyle = "white";
        ctx.strokeRect(x*cw, y*cw, cw, cw);
    }

    function check_collision(x, y, array) {
        for(var i = 0; i < array.length; i++) {
            if(array[i].x == x && array[i].y == y)
             return true;
        }
        return false;
    }

    $(document).keydown(function(e) {
        var key = e.which;
        if(key == "37" && d != "right") d = "left";
        else if(key == "38" && d != "down") d = "up";
        else if(key == "39" && d != "left") d = "right";
        else if(key == "40" && d != "up") d = "down";
    })
})

代码来源：http://thecodeplayer.com/walkthrough/html5-game-tutorial-make-a-snake-game-using-html5-canvas-jquery

任何帮助将不胜感激：）

Answer 1

var tail与function paint()一样位于snake_array.unshift(tail);，因此可以访问var。

Answer 2

tail在if语句中声明，因此它不受范围限制。如果它在一个函数中，你将失去范围。

如评论中所述，JavaScript只有功能级别的范围。

以下是您可以在控制台中运行的简单示例：

if (1>0) {
    var derp = "herp";
}
console.log(derp);
//outputs "herp"

在声明范围之外使用局部变量;这为什么有效？

2 个答案: