Question

我在Visual Studio 2010中有一个功能正常的项目。我将该项目转移到了VS2012，我得到了OutOfMemoryException。我知道为什么我会得到例外，因为我在2010年得到了同样的例子。它发生的原因是因为应用程序运行一个遗传算法，产生几个后代，其中每个子项生成的都由一个大对象组成（int array [500,200， 7]）。我减少了在每个交叉上生成了多少后代，并且能够摆脱异常，我还必须添加offspring.clear()，即使它是一个局部变量。在VS2012中，垃圾收集似乎永远不会占用应该释放的offspring数组。我甚至在GC.Collect()中添加它应该发生的地方。我很困惑为什么使用相同的代码，程序只会继续消耗VS2012中的内存。

    /// <summary>
    /// Runs the genetic algorithm
    /// </summary>
    public void RunAlgorithm()
    {
        for (int i = 0; i < progeny; i++)
            schedules.Add(new Schedule(true));

        schedules.Sort();
        best = schedules[0];

        while (best.unscheduled.Count > 15)
        {
            List<Scheduling.Schedule> offspring = GetOffspring();
            offspring.Sort();

            if (offspring[0].unscheduled.Count < best.unscheduled.Count)
                best = offspring[0];

            schedules.Clear();

            for (int s = 0; s < progeny; s++)
                schedules.Add(offspring[s]);

            offspring.Clear();
        }
    }

    public List<Scheduling.Schedule> GetOffspring()
    {
        List<Scheduling.Schedule> offspring = new List<Schedule>();

        int parentSize = (int)(schedules.Count * poolSizePcnt);

        for (int p1 = 0; p1 < parentSize; p1++)
        {
            for (int p2 = p1 + 1; p2 < parentSize; p2++)
            {
                Schedule[] children = Breed(schedules[p1], schedules[p2]);
                offspring.Add(children[0]);
                offspring.Add(children[1]);
            }
        }

        return offspring;
    }

    /// <summary>
    /// Returns an array of 2 children from the breeding of two parents with a single crossover point and potential mutation on the alleles.
    /// </summary>
    /// <param name="p1">Parent One</param>
    /// <param name="p2">Parent two</param>
    /// <returns></returns>
    public Schedule[] Breed(Schedule p1, Schedule p2)
    {
        Schedule c1 = new Schedule();
        c1.schedule = new int[p1.schedule.GetUpperBound(0) + 1, p1.schedule.GetUpperBound(1) + 1, p1.schedule.GetUpperBound(2) + 1];
        Schedule c2 = new Schedule();
        c2.schedule = new int[p1.schedule.GetUpperBound(0) + 1, p1.schedule.GetUpperBound(1) + 1, p1.schedule.GetUpperBound(2) + 1];

        //randomized crossover point from min to max
        int crssPnt = (int)(Schedule.rand.Next(min, max) / (10.0) * Schedule.courseIDdict.Count);

        for (int c = 0; c < crssPnt; c++)
        {
            int cID = Schedule.courseIDdict[c].id;
            //TODO: if cID is contained within a list, prevent from certain moves, e.g. to D
            for (int i = 1; i <= 6; i++)
            {
                int random = Schedule.rand.Next(0, mutationRate);

                if (p1.schedule[0, cID, i] >= 1)
                {
                    if (rand1 == random)//introduce mutation if the random number is hit
                        c1.schedule[0, cID, Schedule.rand.Next(1, 7)] = 1;
                    else
                        c1.schedule[0, cID, i] = 1;
                }

                if (p2.schedule[0, cID, i] >= 1)
                {
                    if (rand2 == random)//introduce mutation if the random number is hit
                        c2.schedule[0, cID, Schedule.rand.Next(1, 7)] = 1;
                    else
                        c2.schedule[0, cID, i] = 1;
                }
            }

        }

        for (int c = crssPnt; c < Schedule.courseIDdict.Count; c++)
        {
            int cID = Schedule.courseIDdict[c].id;

            for (int i = 1; i <= 6; i++)
            {
                int random = Schedule.rand.Next(0, mutationRate);

                if (p1.schedule[0, cID, i] >= 1)
                {
                    if (rand2 == random)//introduce mutation if the random number is hit
                        c2.schedule[0, cID, Schedule.rand.Next(1, 7)] = 1;
                    else
                        c2.schedule[0, cID, i] = 1;
                }


                if (p2.schedule[0, cID, i] >= 1)
                {
                    if (rand1 == random)//introduce mutation if the random number is hit
                        c1.schedule[0, cID, Schedule.rand.Next(1, 7)] = 1;
                    else
                        c1.schedule[0, cID, i] = 1;
                }
            }
        }

        c1.AddStudentsToClasses();
        c2.AddStudentsToClasses();

        return new[] { c1, c2 };
    }

Answer 1

VS中有（任何CPU）配置，然后有一个构建目标下拉列表（在2012年）Project-＆gt; Properties-＆gt; Buid选项卡。 Build Target经常被设置为x86，当有大量ram可用时，你会看到Out of Memory异常被抛出。例如，您可以通过构建目标选项设置任何cpu配置并仍在为x86构建。当您达到2GB的RAM使用量时，这将导致内存不足异常。

VS2012 OutOfMemoryException与VS2010无异常工作

1 个答案: