我正在创建一个对象类型为Employee的数组,但其中一个属性未按预期工作。
我使用的是Employee类型的对象数组,我用构造函数语句块定义。构造函数的一部分是,如果没有定义nickname属性,则将第一个名称用作昵称。此外,如果未定义班次,则将其设置为" 1。"
当我调试时,我看到昵称和移位总是设置,好像没有为这些属性定义任何内容,即使它们是。是什么给了什么?
细节:在Win9机器上运行IE9,也使用jquery2.1。
以下是代码:
// make sure doc ready first
$(document).ready(function(){
function Employee(firstname, lastname, nickname, employeeID, shift, serviceTruck, pickupTruck, serviceTruckWO){
this.firstname = firstname;
this.lastname = lastname;
/*
* Check if the nickname is present. If not,
* set as lastname. Credit to SO for
* how to do this properly, ref
* http://stackoverflow.com/questions/27509/detecting-an-undefined-object-property-in-javascript
*/
if (typeof this.nickname === "undefined") {
this.nickname = this.firstname;
}
else {
this.nickname = nickname;
}
this.employeeID = employeeID;
if (typeof this.shift === "undefined") {
this.shift = "1";
}
else {
this.shift = shift;
}
this.serviceTruck = serviceTruck;
this.pickupTruck = pickupTruck;
this.serviceTruckWO = serviceTruckWO;
}
var Employees = new Array();
Employees[0] = new Employee("John", "Smith", "Smithy", "1234", "2", "ST1", "PU1", "WO1");
Employees[1] = new Employee("Jane", "Doe", "", "1235", "", "ST2", "PU2", "WO2");
});
答案 0 :(得分:2)
在设置之前检查this.nickname
,因此其类型仍未定义。
if (typeof nickname === "undefined") {
this.nickname = this.firstname;
}
else {
this.nickname = nickname;
}
答案 1 :(得分:1)
您需要先从输入设置它们。
function Employee(firstname, lastname, nickname, employeeID, shift, serviceTruck, pickupTruck, serviceTruckWO){
this.firstname = firstname;
this.lastname = lastname;
/*
* Check if the nickname is present. If not,
* set as lastname. Credit to SO for
* how to do this properly, ref
* http://stackoverflow.com/questions/27509/detecting-an-undefined-object-property-in-javascript
*/
this.nickname = nickname;
if (typeof this.nickname === "undefined") {
this.nickname = this.firstname;
}
else {
this.nickname = nickname;
}
this.employeeID = employeeID;
this.shift = shift ;
if (typeof this.shift === "undefined") {
this.shift = "1";
}
else {
this.shift = shift;
}
this.serviceTruck = serviceTruck;
this.pickupTruck = pickupTruck;
this.serviceTruckWO = serviceTruckWO;
}
var Employees = new Array();
Employees[0] = new Employee("John", "Smith", "Smithy", "1234", "2", "ST1", "PU1", "WO1");
Employees[1] = new Employee("Jane", "Doe", "", "1235", "", "ST2", "PU2", "WO2");
答案 2 :(得分:1)
或者所有酷孩子使用的真正简短的版本:
this.nickname = nickname || firstname;
或者,如果可以为昵称传递 null ,则必须明确检查:
this.nickname = nickname === null ? firstname : nickname;
或者,如果它可以是未定义或 null :
this.nickname = nickname && nickname !== null ? nickname : firstname;
如果你看一下jQuery等人的文库,你会发现这很多。
我喜欢第一个,这就是我使用的。 :)
答案 3 :(得分:0)
您访问传递给this
对象上的构造函数的变量,而不是先将它们分配给this
。
答案 4 :(得分:0)
我就是这样做的:
function Employee(firstname, lastname, nickname, employeeID, shift, serviceTruck, pickupTruck, serviceTruckWO){
this.firstname = firstname;
this.lastname = lastname;
this.employeeID = employeeID;
this.serviceTruck = serviceTruck;
this.pickupTruck = pickupTruck;
this.serviceTruckWO = serviceTruckWO;
this.nickname = nickname; // if all right, already set
this.shift = shift; // if all right, already set
// special cases, else not needed cause you already define the value ;)
if (nickname === "" || nickname === null || nickname === undefined)
this.nickname = this.firstname;
if (shift === "" || shift === null || shift === undefined)
this.shift = "1";
}