Question

我有以下方法，我想要一个带有几个字段的User对象，即name，address.country等等。

我试图在列表中获取国家/地区数据但不能（仅显示名称数据）。

public List<User> getActiveUsers() {
    Criteria userCriteria = getSession().createCriteria(User.class, "user")
    .createAlias("address", "address");

    userCriteria.setProjection(Projections.projectionList().add(Projections.property("name"), "name").add(Projections.property("address.country"), "country"));
    userCriteria.setResultTransformer(Transformers.aliasToBean(User.class));

    return userCriteria.list();
}

People.hbm.xml文件的片段

<class name="model.People" table="PEOPLE">
    <id column="PEOPLE_ID" name="id" type="long">
        <generator class="native" />
    </id>

    ....

    <joined-subclass extends="model.People" name="model.User" table="USER">
        <key column="PEOPLE_ID" />
        <many-to-one class="model.BusinessAddress" column="ADDRESS_ID" name="address" />
    </joined-subclass>
</class>

java pojo＆＃39;

public class User extends People implements Serializable {
    //other fields
    protected BusinessAddress address = new BusinessAddress();
}

public class BusinessAddress extends Address implements Serializable {
    //other fields
}

public abstract class Address implements Serializable {
    //other fields
    public String country;

    public String getCountry() {
        return country;
    }

    public void setCountry(String country) {
        this.country = country;
    }
}

错误堆栈跟踪：

org.hibernate.PropertyNotFoundException: Could not find setter for country on class model.User
 at org.hibernate.property.ChainedPropertyAccessor.getSetter(ChainedPropertyAccessor.java:67)
 at org.hibernate.transform.AliasToBeanResultTransformer.initialize(AliasToBeanResultTransformer.java:118)
 at org.hibernate.transform.AliasToBeanResultTransformer.transformTuple(AliasToBeanResultTransformer.java:81)
 at org.hibernate.loader.criteria.CriteriaLoader.getResultColumnOrRow(CriteriaLoader.java:158)
 at org.hibernate.loader.Loader.getRowFromResultSet(Loader.java:647)
 at org.hibernate.loader.Loader.doQuery(Loader.java:745)
 at org.hibernate.loader.Loader.doQueryAndInitializeNonLazyCollections(Loader.java:270)
 at org.hibernate.loader.Loader.doList(Loader.java:2449)
 at org.hibernate.loader.Loader.listIgnoreQueryCache(Loader.java:2192)
 at org.hibernate.loader.Loader.list(Loader.java:2187)
 at org.hibernate.loader.criteria.CriteriaLoader.list(CriteriaLoader.java:119)
 at org.hibernate.impl.SessionImpl.list(SessionImpl.java:1706)
 at org.hibernate.impl.CriteriaImpl.list(CriteriaImpl.java:347)
 at dao.PeopleDAO.getActiveUsers(PeopleDAO.java:100)
 .....

国家/地区是地址的一部分，而不是用户。我找不到地址。任何帮助将不胜感激。

此外，show_sql = true时的hibnernate查询显示sql是正确的

Answer 1

我最初看到了这个解决方案 Populate child bean with Transformers.aliasToBean in Hibernate 但是对于Hibernate4，我使用的是Hibernate3，所以我没有进一步追求它。但是我仍然在寻找一个解决方案，所以我想看看我是否可以重新创建hibernate4类，事实证明你可以这样做。

我从链接创建了AliasToBeanNestedResultTransformer.java 然后这个 https://github.com/hibernate/hibernate-orm/blob/master/hibernate-core/src/main/java/org/hibernate/transform/AliasedTupleSubsetResultTransformer.java 然后这个 https://github.com/hibernate/hibernate-orm/blob/master/hibernate-core/src/main/java/org/hibernate/transform/TupleSubsetResultTransformer.java

然后编译这些类似乎工作正常。

但是，我的最终解决方案是实际使用Hibernate Search

“org.hibernate.PropertyNotFoundException：无法找到关联对象的setter”

1 个答案: