从curl输出中搜索并打印字符串和值

Question

我有一个curl命令，它返回一行，但有一个冗长的响应体。并且需要搜索特定字符串并打印结果。

例如，这是curl的输出。我可以使用bash脚本打印centos的状态值，这是＆＃34; true＆＃34;？或者我应该使用不同的脚本/程序语言？脚本应该基本输出为state = true。注意，有两个状态＆＃34;输出中的值

~]# curl -v -k -u test:test https://myurl.com/api/state



"name":"centos","type":"disc","state":true},{"partitions":5},"auth_mechanisms":  [{"name":"PLAIN","description":"PLAIN authentication"}],   [{"name":"suse","type":"ram","state":true}]

Answer 1

您可以尝试使用此sed组合命令

sed 's/},/\n/g' file | sed -nr '/centos/ s/.*:(.*)$/\1/p'

示例：

$ echo '"name":"centos","type":"disc","state":true},{"partitions":5},"auth_mechanisms":  [{"name":"PLAIN","description":"PLAIN authentication"}],   [{"name":"suse","type":"ram","state":true}]' | sed 's/},/\n/g' | sed -nr '/centos/ s/.*:(.*)$/\1/p'
true