Question

我有一个SQL查询，我在那里提取员工时间卡信息。它提取姓名，工资单ID，Locaiton，正常工作时间和加班时间。但是，我无法弄清楚如何使用case和Sum正确地舍入常规和加班时间。下面是我的代码，不是四舍五入。

SELECT        Employee_Tb.First_Name + ' ' + Employee_Tb.Last_Name AS Name, Employee_Tb.Home_Store_Id, Employee_Tb.Payroll_Id, 
                         CASE WHEN SUM(Payroll_Hours_Tb.Hours_Worked) > 40.0 THEN 40.0 ELSE Round(SUM(Payroll_Hours_Tb.Hours_Worked), 2) END AS RegHours, 
                         CASE WHEN SUM(Payroll_Hours_Tb.Hours_Worked) > 40.0 THEN Round(SUM(Payroll_Hours_Tb.Hours_Worked), 2) - 40.0 ELSE 0.0 END AS OTHours
FROM            Employee_Tb INNER JOIN
                         Payroll_Hours_Tb ON Employee_Tb.Employee_Id = Payroll_Hours_Tb.Employee_Id
WHERE        (Payroll_Hours_Tb.Work_Date BETWEEN @startdate AND @enddate)
GROUP BY Employee_Tb.Payroll_Id, Employee_Tb.First_Name, Employee_Tb.Last_Name, Employee_Tb.Home_Store_Id
ORDER BY Employee_Tb.Home_Store_Id

结果的一个例子是：正常时间“21.91999999”
它应该是：“21.92”

Answer 1

尝试使用

convert(int,Round(SUM(Payroll_Hours_Tb.Hours_Worked), 0))

这将消除额外的整数

如何使用Case和Sum进行舍入

1 个答案: