Question

如何让这个php脚本重复表中的行数？我有点迷失如何开始，再次感谢。

<?php
$con = mysqli_connect("localhost", "root", "xxx", "xxx");

//    Check    connection

if (mysqli_connect_errno())
    {
    echo "Failed    to    connect    to    MySQL:    " . mysqli_connect_error();
    }

$result = mysqli_query($con, "SELECT    *    FROM    caseStudies");
$row = mysqli_fetch_array($result);

for ($i = 0; $i < 1; $i++)
    {
    echo "<div    class='case'    id='case$i'>";
    echo "<div    class='row'>";
    echo "<div    class='header'>";
    echo '<h4>' . $row['caseName'] . '</h4>';
    echo "</div>";
    echo "</div>";
    echo "<div    class='row'>";
    echo "<div    class='caseimg'>";
    echo '<img    src="' . $row['caseImage'] . '"    class="Responsive    image"/>';
    echo "</div>";
    echo "<div    class='caseimg'>";
    echo '<img    src="' . $row['caseImage'] . '"    class="Responsive    image"/>';
    echo "</div>";
    echo "<div    class='caseimg'>";
    echo '<img    src="' . $row['caseImage'] . '"    class="Responsive    image"/>';
    echo "</div>";
    echo "</div>";
    $i++;
    }
}

Answer 1

你在forloop中的状况不正确。使用方法：

$i = 0;
while ($row = mysqli_fetch_assoc($result)) {
    echo ...
    $i++; //if you need $i
}

代替

Answer 2

您可以使用mysqli_num_rows和mysqli_fetch_assoc()

试试这个： -

$result = mysqli_query($con,"SELECT * FROM caseStudies");

$ispresent = @mysqli_num_rows($result);    

$i = 0;

if($ispresent > 0) // if row present then only run your while loop
{

    while($row = mysqli_fetch_assoc($result))
    {

        echo    "<div    class='case'    id='case$i'>";
            echo    "<div    class='row'>";
            echo    "<div    class='header'>";
            echo    '<h4>'    .    $row['caseName']    .    '</h4>';
            echo    "</div>";
            echo    "</div>";
            echo    "<div    class='row'>";
            echo    "<div    class='caseimg'>";
            echo    '<img    src="'    .    $row['caseImage']    .    '"    class="Responsive    image"/>';
            echo    "</div>";
            echo    "<div    class='caseimg'>";
            echo    '<img    src="'    .    $row['caseImage']    .    '"    class="Responsive    image"/>';
            echo    "</div>";
            echo    "<div    class='caseimg'>";
            echo    '<img    src="'    .    $row['caseImage']    .    '"    class="Responsive    image"/>';
            echo    "</div>";
            echo    "</div>";

         $i++;
    }

 }

Answer 3

您可以使用while或foreach

来完成此操作

<?php
$con=mysqli_connect("localhost","root","xxx","xxx");
//    Check    connection
if    (mysqli_connect_errno())    {
echo    "Failed    to    connect    to    MySQL:    "    .    mysqli_connect_error();
}
$result    =    mysqli_query($con,"SELECT    *    FROM    caseStudies");
$i=1;
while($row    =    mysqli_fetch_array($result))
{

echo    "<div    class='case'    id='case$i'>";
echo    "<div    class='row'>";
echo    "<div    class='header'>";
echo    '<h4>'    .    $row['caseName']    .    '</h4>';
echo    "</div>";
echo    "</div>";
echo    "<div    class='row'>";
echo    "<div    class='caseimg'>";
echo    '<img    src="'    .    $row['caseImage']    .    '"    class="Responsive    image"/>';
echo    "</div>";
echo    "<div    class='caseimg'>";
echo    '<img    src="'    .    $row['caseImage']    .    '"    class="Responsive    image"/>';
echo    "</div>";
echo    "<div    class='caseimg'>";
echo    '<img    src="'    .    $row['caseImage']    .    '"    class="Responsive    image"/>';
echo    "</div>";
echo    "</div>";
$i++;               
}
?>

Answer 4

在这种情况下，您应该使用WHILE循环，如下所示：

$con=mysqli_connect("localhost","root","xxx","xxx");
//    Check    connection
if    (mysqli_connect_errno())    {
  echo    "Failed    to    connect    to    MySQL:    "    .    mysqli_connect_error();
}
$result    =    mysqli_query($con,"SELECT    *    FROM    caseStudies");
$i=0;
while($row    =    mysqli_fetch_array($result)){
  echo    "<div    class='case'    id='case$i++'>";
  echo    "<div    class='row'>";
  echo    "<div    class='header'>";
  echo    '<h4>'    .    $row['caseName']    .    '</h4>';
  echo    "</div>";
  echo    "</div>";
  echo    "<div    class='row'>";
  echo    "<div    class='caseimg'>";
  echo    '<img    src="'    .    $row['caseImage']    .    '"    class="Responsive    image"/>';
  echo    "</div>";
  echo    "<div    class='caseimg'>";
  echo    '<img    src="'    .    $row['caseImage']    .    '"    class="Responsive    image"/>';
  echo    "</div>";
  echo    "<div    class='caseimg'>";
  echo    '<img    src="'    .    $row['caseImage']    .    '"    class="Responsive    image"/>';
  echo    "</div>";
  echo    "</div>";
}

你可以使用for循环，如果你真的想要/需要通过用for mysqli_num_rows（）函数替换for循环的比较部分中的1：

for($i=0;$i<mysqli_num_rows($result);$i++)

Answer 5

$countRes = mysqli_num_rows($result);
for($i=0; $i<$countRes; $i++){ ... }

使用mysqli_num_rows($result)获取记录数。

Answer 6

使用： while($row = mysqli_fetch_array($result))

而不是： for($i = 0; $i < 1; $i++)

Answer 7

你可以使用while循环，因为其他人说每行都会这样做

（虽然会自动停止和最后一行，但您不需要知道您拥有的行数）

如果您只需要两次，请保留您的代码但是：您有缺少</div>

编辑：您的编辑似乎已更正了遗失的</div>

PHP从表中收集所有行

7 个答案: