将图像保存在django中的临时文件中

时间:2014-06-04 09:39:07

标签: python django python-imaging-library

我是python和django的新手。我使用django开发了一个项目。这里所有图像都有水印。我使用以下代码为所有图像加水印......

from PIL import Image
    def image_watermark(request,image_id):
        photo = Photo.objects.get(pk=image_id)
        watermark = Image.open('{0}/{1}'.format(settings.MEDIA_ROOT,'wmark.png'))
        img = Image.open(photo.photo.file)

        img.paste(watermark,(img.size[0]-watermark.size[0],img.size[1]- watermark.size[1]),watermark)

        img.save('{0}/{1}'.format(settings.MEDIA_ROOT,photo.photo.name), quality=80)


        wrapper = FileWrapper(open(photo.photo.url, 'rb'))
        response = StreamingHttpResponse(wrapper, 'image/jpeg')
        response['Content-Length'] = os.path.getsize(photo.photo.url)
        response['Content-Disposition'] = 'attachment; filename=photo.jpg'
        return response

我的所有图像都已加水印了。但问题是,作为用户,如果我下载这些图像,我发现下载的图像也有水印,但我想下载实际图像,而不是水印图像,我该如何解决这个问题?

1 个答案:

答案 0 :(得分:3)

您需要将带水印的图像存储到其他文件中。 首先,您需要创建另一列来存储水印图像。

class Photo(models.Model):
    ...
    watermarked_photo = ImageField()

然后将水印图像保存到该列中。

from PIL import Image
def image_watermark(request,image_id):
    photo = Photo.objects.get(pk=image_id)

    # Only need to watermark when there's no watermark
    if not photo.watermarked_photo.name:
        photo.watermarked_photo.name = 'watermarked_' + photo.photo.name
        watermark = Image.open('{0}/{1}'.format(settings.MEDIA_ROOT,'wmark.png'))
        img = Image.open(photo.photo.file)
        img.paste(watermark,(img.size[0]-watermark.size[0],img.size[1]- watermark.size[1]),watermark)
        img.save('{0}/{1}'.format(settings.MEDIA_ROOT, photo.watermarked_photo.name), quality=80)
        photo.save()

    wrapper = FileWrapper(open(photo.watermarked_photo.url, 'rb'))
    response = StreamingHttpResponse(wrapper, 'image/jpeg')
    response['Content-Disposition'] = 'attachment; filename=photo.jpg'
    return response

我的Django技能有点生疏,所以如果没有一些修改,这些代码可能无法正常工作。但这个想法应该是可靠的。

如果您只想使用临时文件,请尝试使用

from PIL import Image
import tempfile

def image_watermark(request,image_id):
    photo = Photo.objects.get(pk=image_id)
    watermark = Image.open('{0}/{1}'.format(settings.MEDIA_ROOT,'wmark.png'))
    img = Image.open(photo.photo.file)
    img.paste(watermark,(img.size[0]-watermark.size[0],img.size[1]- watermark.size[1]),watermark)

    tmpfile = tempfile.TemporaryFile()
    img.save(tmpfile, img.format, quality=80)

    tmpfile.seek(0)
    wrapper = FileWrapper(tmpfile)
    response = StreamingHttpResponse(wrapper, 'image/jpeg')
    response['Content-Disposition'] = 'attachment; filename=photo.jpg'
    return response