目前正在学习JavaScript并尝试创建扩展菜单。
我试图找到同一个类的所有元素,并在点击NodeList中的所有元素时设置CSS值。我在控制台中看到的错误是:
Cannot read property 'style' of undefined
我知道它与for循环有关,没有正确设置变量;只是不太确定它是什么。
的jsfiddle
HTML
<div class="master">
<a href="#" id="btn-nav">
<span></span>
<span>Menu</span>
<span></span>
</a>
<nav id="main-nav">
<div class="wrapper">
<div class="background">
<div class="slice"></div>
<div class="slice"></div>
<div class="slice"></div>
<div class="slice"></div>
<div class="slice"></div>
<div class="slice"></div>
<div class="slice"></div>
<div class="slice"></div>
<div class="slice"></div>
<div class="slice"></div>
<div class="slice"></div>
<div class="slice"></div>
</div>
</div>
</nav>
</div><!-- end master -->
CSS
@import url(http://fonts.googleapis.com/css?family=Droid+Sans);
body {
background: #2980b9;
font-family: 'Droid Sans', sans-serif;
}
#btn-nav {
position:absolute;
left:10px;
top:10px;
width:30px;
height:30px;
display:block;
z-index:1;
}
#btn-nav span:nth-child(2) {
top:10px;
}
#btn-nav span:nth-child(3) {
top:20px;
}
#btn-nav span {
height: 4px;
width: 30px;
background: white;
content: "";
text-indent: -999em;
display:inline-block;
position:absolute;
zoom: 1;
top:0px;
left:0px;
text-align:center;
-webkit-transition: top .3s cubic-bezier(0.165,.84,.44,1);
-webkit-transform: rotate(0deg);
}
#btn-nav:hover > span {
top:10px;
-webkit-animation: rotateAni .5s 1s forwards;
}
#btn-nav:hover > span:nth-child(1) {
-webkit-animation: rotateAni .5s .5s forwards, expandAni .3s .8s forwards;
}
#btn-nav:hover > span:nth-child(2) {
-webkit-animation: rotateAni .5s .5s forwards, expandAni-2 .3s .8s forwards;
}
#btn-nav:hover > span:nth-child(3) {
-webkit-animation: rotateAni .5s .5s forwards, expandAni-3 .3s .8s forwards;
}
@-webkit-keyframes rotateAni {
0% {-webkit-transform: rotate(0deg);}
100% {-webkit-transform: rotate(90deg);}
}
@-webkit-keyframes expandAni {
0% {left:0;}
100% {left:-10px;}
}
@-webkit-keyframes expandAni-2 {
0% {left:0;}
100% {left:0px;}
}
@-webkit-keyframes expandAni-3 {
0% {left:0;}
100% {left:10px;}
}
#main-nav {
position:fixed;
left:0;
top:0;
display:block;
width:100%;
height:100%;
z-index:-1;
}
#main-nav .wrapper {
display:table;
width:100%;
height:100%;
}
.slice {
width:25%;
height:30%;
float:left;
background:black;
opacity:0;
-webkit-transition: 1s;
}
.background {
position:absolute;
left:0;
top:0;
width:100%;
height:100%;
z-index:-1;
}
JS
(function () {
'use strict';
var menuBtn = document.getElementById('btn-nav');
var slice = document.querySelectorAll('.slice');
for(var i = 0; i <= slice.length; i++) {
var boxes = slice[i];
}
menuBtn.addEventListener('click', function() {
boxes.style.opacity = 1;
}, false);
}());
答案 0 :(得分:3)
您需要将for循环放在事件中,因为它当前所做的只是设置LAST切片的不透明度。
var menuBtn = document.getElementById('btn-nav');
var slice = document.querySelectorAll('.slice');
menuBtn.addEventListener('click', function() {
for(var i = 0; i < slice.length; i++) {
slice[i].style.opacity = 1;
}
}, false);
答案 1 :(得分:1)
我喜欢你的代码,以下是给你的礼物:http://jsfiddle.net/dXv68/3/
这是秘密:
(function () {
'use strict';
var menuBtn = document.getElementById('btn-nav');
var slice = document.querySelectorAll('.slice');
menuBtn.addEventListener('click', function() {
for(var key in slice) {
slice[key].style.opacity = 1;
}
}, false);
}());