如何使用Spring Data CouchBase'findAll(Iterable <id>)'方法?</id>

时间:2014-06-03 12:34:35

标签: couchbase spring-data-couchbase

我试图使用Spring-Data-Couchbase。

我想从findAll(Iterable)方法获取List。 我设置了所有&#39;到我的生产视图。

但是,我遇到了例外。 我如何使用findAll(Iterable)方法?

以下是示例代码和例外。

文件类:

@Document
public class User {
    @Id
    private String id;
    private String userSeq;
}

存储库类:

public interface UserRepository extends CouchbaseRepository<User, String> {
}

服务类:

//List<String> get the Same result & exception.
Set<String> friendSet = new HashSet<String>();
friendSet.add("User8");
friendSet.add("User6");

userRepository.findAll(friendSet)

例外:

Caused by: java.util.concurrent.ExecutionException: OperationException: SERVER: bad_request Reason: invalid UTF-8 JSON: {{error,{2,"lexical error: invalid char in json text.\n"}},
                 "[User8, User6]"}
at com.couchbase.client.internal.HttpFuture.waitForAndCheckOperation(HttpFuture.java:98)
at com.couchbase.client.internal.HttpFuture.get(HttpFuture.java:82)
at com.couchbase.client.internal.HttpFuture.get(HttpFuture.java:72)
at com.couchbase.client.CouchbaseClient.query(CouchbaseClient.java:778)
... 66 more
Caused by: OperationException: SERVER: bad_request Reason: invalid UTF-8 JSON: {{error,{2,"lexical error: invalid char in json text.\n"}},
                 "[User8, User6]"}
at com.couchbase.client.protocol.views.NoDocsOperationImpl.parseError(NoDocsOperationImpl.java:110)
at com.couchbase.client.protocol.views.ViewOperationImpl.handleResponse(ViewOperationImpl.java:68)
at com.couchbase.client.http.HttpResponseCallback.completed(HttpResponseCallback.java:103)
at com.couchbase.client.http.HttpResponseCallback.completed(HttpResponseCallback.java:51)
at org.apache.http.concurrent.BasicFuture.completed(BasicFuture.java:115)
at org.apache.http.nio.protocol.HttpAsyncRequester$RequestExecutionCallback.completed(HttpAsyncRequester.java:376)
at org.apache.http.concurrent.BasicFuture.completed(BasicFuture.java:115)
at org.apache.http.nio.protocol.BasicAsyncClientExchangeHandler.responseCompleted(BasicAsyncClientExchangeHandler.java:179)
at org.apache.http.nio.protocol.HttpAsyncRequestExecutor.processResponse(HttpAsyncRequestExecutor.java:349)
at org.apache.http.nio.protocol.HttpAsyncRequestExecutor.inputReady(HttpAsyncRequestExecutor.java:236)
at org.apache.http.impl.nio.DefaultNHttpClientConnection.consumeInput(DefaultNHttpClientConnection.java:267)
at org.apache.http.impl.nio.DefaultHttpClientIODispatch.onInputReady(DefaultHttpClientIODispatch.java:165)
at org.apache.http.impl.nio.DefaultHttpClientIODispatch.onInputReady(DefaultHttpClientIODispatch.java:51)
at org.apache.http.impl.nio.reactor.AbstractIODispatch.inputReady(AbstractIODispatch.java:113)
at org.apache.http.impl.nio.reactor.BaseIOReactor.readable(BaseIOReactor.java:159)
at org.apache.http.impl.nio.reactor.AbstractIOReactor.processEvent(AbstractIOReactor.java:338)
at org.apache.http.impl.nio.reactor.AbstractIOReactor.processEvents(AbstractIOReactor.java:316)
at org.apache.http.impl.nio.reactor.AbstractIOReactor.execute(AbstractIOReactor.java:277)
at org.apache.http.impl.nio.reactor.BaseIOReactor.execute(BaseIOReactor.java:105)
at org.apache.http.impl.nio.reactor.AbstractMultiworkerIOReactor$Worker.run(AbstractMultiworkerIOReactor.java:584)
... 1 more

1 个答案:

答案 0 :(得分:1)

在致电findAll(...)之前,您必须引用id:s。

    Set<String> friendSet = new HashSet<String>();
    friendSet.add("\"User8\"");
    friendSet.add("\"User6\"");

如果id:s没有被​​引用,发送到Couchbase服务器的keys参数看起来像[User8,User6],这不是有效的JSON,因此是例外。非常令人惊讶的行为......