Question

我有一张包含这样记录的表格。

S.No   | Name   |  Date     |  Type  
1      | test   | 2014-1-1  |   In
2      | test   | 2014-1-1  |   Out
3      | test12 | 2014-1-1  |   In
4      | test12 | 2014-1-1  |   Out
5      | test123| 2014-1-1  |   In

所需要的是一个sql查询，它只返回type = In的记录，并且在同一天没有为它做过type = out。我试过了从dbo.TimeCheckInOut中选择日期，COUNT（*）作为计数，其中EmployeeNo =＆＃39; E012＆＃39;按日期分组。这不起作用..我怎样才能返回那些类型只有

的记录

Answer 1

如果你想获得只有type = In且没有type = out 的记录，那么我建议这样做：

select *
from Table1 as t
where
    t.[Type] = 'In' and
    not exists (
        select *
        from Table1 as tt where tt.Name = t.Name and tt.[Type] = 'Out'
    )

<强> sql fiddle demo

Answer 2

试试这个

SELECT Name,Date,Type From
Table 1 Where Type = 'In' And 
              Name Not In (Select Name From Table1 Where Type = 'Out')

<强> Fiddle Demo

<强> O / P

SNO NAME    DATE                            TYPE
------------------------------------------------
5   test123 January, 01 2014 00:00:00+0000  In

Answer 3

SELECT * FROM table1 t1
WHERE t1.type = 'IN' AND NOT EXISTS (SELECT * FROM  table1 t2 WHERE t2.type = 'OUT' AND t2.name = t1.name)

上述查询将产生所需的输出。

SQL Fiddle

Answer 4

您可以使用以下查询..

select * from test a
where a.Type='In'
and not exists (select null from test b  where b.Type='Out' and b.Name=a.Name)

Fiddle Here

Answer 5

另一种方法

select in.* 
  from table in 
  left join table out
    on out.name = in.name 
   and in.type = 'In' 
   and out.type = 'Out' 
 where out.name is null

sql查询返回在同一个表中没有重复记录的记录

5 个答案: