Question

我正在创建应用程序，用户输入数据进行搜索，然后应用程序将其发送到服务器，然后服务器将搜索结果发送回客户端。

我收到错误，我无法理解其含义。

这是我应用程序中的网络代码，这里是link to full code

 public class GetDatafromDB_Searchresult {

        public String getDataFromDB() {


            try {

                httpclient = new DefaultHttpClient();
                httppost = new HttpPost("http://192.168.0.106/test/search1.php"); // make sure the url is correct.
                //add your data
                nameValuePairs = new ArrayList<NameValuePair>(2);
                // Always use the same variable name for posting i.e the android side variable name and php side variable name should be similar,
                nameValuePairs.add(new BasicNameValuePair("carat1", strcolor1.toString().trim()));
                nameValuePairs.add(new BasicNameValuePair("carat2", strcolor2.toString().trim()));
                nameValuePairs.add(new BasicNameValuePair("color1", strclarity1.toString().trim()));
                nameValuePairs.add(new BasicNameValuePair("color2", strclarity2.toString().trim()));
                nameValuePairs.add(new BasicNameValuePair("cut1", strcut1.toString().trim()));
                nameValuePairs.add(new BasicNameValuePair("cut2", strcut2.toString().trim()));
                nameValuePairs.add(new BasicNameValuePair("shape1", strshape1.toString().trim()));
                nameValuePairs.add(new BasicNameValuePair("shape2", strshape2.toString().trim()));
                nameValuePairs.add(new BasicNameValuePair("stones", strstone.toString().trim()));


                // $Edittext_value = $_POST['Edittext_value'];

                    httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
                    //Execute HTTP Post Request
                    response = httpclient.execute(httppost);
                HttpEntity entity= response.getEntity();
                {
                    if(entity!=null)
                    {
                        entity.consumeContent();
                    }
                }

                ResponseHandler<String> responseHandler = new BasicResponseHandler();
                final String response1 = httpclient.execute(httppost, responseHandler);
                System.out.println("Response : " + response1);

            } catch (Exception e) {
                e.printStackTrace();
                System.out.println("Exception : " + e.getMessage());

            }


            return response1;

        }
    }

这是我的服务器端代码

  <?php
$hostname_localhost ="localhost";
$database_localhost ="testdb";
$username_localhost ="root";
$password_localhost ="";
$localhost = mysql_connect($hostname_localhost,$username_localhost,$password_localhost)
or
trigger_error(mysql_error(),E_USER_ERROR);

 mysql_select_db($database_localhost, $localhost);

$carat1 = $_POST['carat1'];
$carat2 = $_POST['carat2'];
$color1 = $_POST['color1'];
$color2 = $_POST['color2'];
$cut1 = $_POST['cut1'];
$cut2 = $_POST['cut2'];
$shape1 = $_POST['shape1'];
$shape2 = $_POST['shape2'];
$stones = $_POST['stones'];


$query_search ="Select * from search1 where 
carats = $carat1 and carats = $carat2 and 
color = '$color1' or color =  '$color2' and 
 cut = '$cut1' or cut = '$cut2' and 
 shape = '$shape1' or shape = '$shape2' and 
 stone ='$stones'";

$query_exec = mysql_query($query_search) or die(mysql_error());


    while($row=mysql_fetch_assoc($query_exec))
            $json_output[]=$row;
      echo json_encode($json_output);

    mysql_close(); 
?>

这是我从logcat

的错误

06-03 14:35:31.269  18943-19053/com.diamond.traders W/System.err﹕ org.apache.http.client.HttpResponseException: Not Found
06-03 14:35:31.269  18943-19053/com.diamond.traders W/System.err﹕ at org.apache.http.impl.client.BasicResponseHandler.handleResponse(BasicResponseHandler.java:71)
06-03 14:35:31.269  18943-19053/com.diamond.traders W/System.err﹕ at org.apache.http.impl.client.BasicResponseHandler.handleResponse(BasicResponseHandler.java:59)
06-03 14:35:31.269  18943-19053/com.diamond.traders W/System.err﹕ at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:657)
06-03 14:35:31.269  18943-19053/com.diamond.traders W/System.err﹕ at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:627)
06-03 14:35:31.269  18943-19053/com.diamond.traders W/System.err﹕ at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:616)
06-03 14:35:31.269  18943-19053/com.diamond.traders W/System.err﹕ at com.diamond.traders.Search_result$GetDatafromDB_Searchresult.getDataFromDB(Search_result.java:692)
06-03 14:35:31.269  18943-19053/com.diamond.traders W/System.err﹕ at com.diamond.traders.Search_result$1.run(Search_result.java:88)
06-03 14:35:31.269  18943-19053/com.diamond.traders W/System.err﹕ at java.lang.Thread.run(Thread.java:841)
06-03 14:35:31.269  18943-19053/com.diamond.traders I/System.out﹕ Exception : Not Found
06-03 14:35:31.269  18943-18943/com.diamond.traders E/log_tag﹕ Error parsing data org.json.JSONException: End of input at character 0 of

Answer 1

我不确定，但我建议你先换一行

nameValuePairs = new ArrayList<NameValuePair>(2);

通过

nameValuePairs = new ArrayList<NameValuePair>();

在您的网络服务中，您必须使用POST而不是GET。

org.apache.http.client.HttpResponseException：在Android中找不到错误

1 个答案: