Question

我在我的脸书app上添加了分享功能。就像＆＃34;说＆＃34;选择了一个用于分享的按钮＆＃34;说＆＃34;在facebook上。点击此按钮时，我只能在我的Facebook页面上看到共享的说法，没有关于我的ios应用程序的任何信息。我怎样才能让每个人都知道这个说法是通过我的iOS应用程序共享的？请帮帮我......

Answer 1

我可能有点晚了。希望这会有所帮助。

您必须使用帐户框架和社交框架与您的应用名称共享。首先确保您已在Facebook上正确设置了应用程序。然后，您可以使用Facebook App ID通过您的应用分享您的帖子。

以下是一个示例代码，向您展示如何将Accounts框架与Social Framework一起使用：

    ACAccountType * facebookAccountType = [self.accountStore accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierFacebook];

    // At first, we only ask for the basic read permission
    NSArray * permissions = @[@"email"];

    NSMutableDictionary *dict = [[NSMutableDictionary alloc] initWithObjectsAndKeys:@"275485699289493", ACFacebookAppIdKey, permissions, ACFacebookPermissionsKey, ACFacebookAudienceOnlyMe, ACFacebookAudienceKey, nil];

    NSArray *accounts = [self.accountStore accountsWithAccountType:facebookAccountType];
    //it will always be the last object with single sign on
    self.facebookAccount = [accounts lastObject];

    [self.accountStore requestAccessToAccountsWithType:facebookAccountType options:dict completion:^(BOOL granted, NSError *error) {
        if (granted && error == nil) {
            /**
             * The user granted us the basic read permission.
             * Now we can ask for more permissions
             **/
            NSArray *readPermissions = @[ @"publish_actions"];
            [dict setObject:readPermissions forKey: ACFacebookPermissionsKey];

            [self.accountStore requestAccessToAccountsWithType:facebookAccountType options:dict completion:^(BOOL granted, NSError *error) {
                if(granted && error == nil) {


                    NSDictionary *parameters = @{@"message": @"This Should Work Perfectly !! "};

                    NSURL *feedURL = [NSURL URLWithString:@"https://graph.facebook.com/me/feed"];

                    SLRequest *feedRequest = [SLRequest
                                              requestForServiceType:SLServiceTypeFacebook
                                              requestMethod:SLRequestMethodPOST
                                              URL:feedURL
                                              parameters:parameters];

                    feedRequest.account = self.facebookAccount;

                    [feedRequest performRequestWithHandler:^(NSData *responseData, 
                                                             NSHTTPURLResponse *urlResponse, NSError *error)
                     {
                         // Handle response
                     }];

                } else {
                    NSLog(@"error is: %@",[error description]);
                }
            }];
        } else {
            NSLog(@"error is: %@",[error description]);
        }
    }];
}

在facebook上分享我的ios应用程序详细信息以及facebook分享

1 个答案: