Question

表格结构

类别表

id      name 
23      Rifle   
24      Bow 
26      Black Powder

Outfitters表

id    name
1     jignesh
2     Ram
3     Ravi

outfitters类别表

id  outfitters_id  categories_id
1    1             23
2    1             24
3    1             26

4    2             23
5    2             26

6    3             26

现在我的问题是什么时候选择（步枪和黑粉）手段（23,26）结果应该是

1     jignesh
2     Ram

当前查询

SELECT distinct outfitters.id,
outfitters.name,
FROM outfitters 
LEFT JOIN categories as c1 ON (c1.categories_id='23') 
LEFT JOIN categories as c2 ON (c2.categories_id='26') 
WHERE outfitters.id=c1.outffiters_id 
OR 
outfitters.id=c2.outffiters_id 
AND outfitters.of_active=1

Answer 1

试试这个

SELECT distinct outfitters.id,
outfitters.name,
FROM outfitters 
LEFT JOIN categories as c1 ON (c1.categories_id='23') 
LEFT JOIN categories as c2 ON (c2.categories_id='26') 
WHERE (outfitters.id=c1.outffiters_id 
OR 
outfitters.id=c2.outffiters_id) 
AND outfitters.of_active=1
GROUP BY outfitters.name

好的，你可以用这样的子查询来做到这一点

SELECT name, id FROM(
    SELECT outfitters.name, outfitters.id, GROUP_CONCAT(outfitters_categories.categories_id) as gc
    FROM outfitters 
    JOIN outfitters_categories ON (outfitters.id = outfitters_categories.outfitters_id)
    WHERE outfitters_categories.categories_id IN (23,26) 
    GROUP BY outfitters.id ) 
tmp WHERE gc = "23,26"

然后你可以简单地用用户选择的任何内容替换23,26

Answer 2

如果您需要必须属于您的2个类别的户外用品商品，您可以通过获取每个必须>＆gt;的服装商的明确计数来实现此目的。或= 2以及您的where过滤器，根据提供的样本数据集

查看小提琴示例

SELECT 
  o.* 
FROM
  Outfitters o 
  JOIN outfitters_categories oc 
    ON (o.id = oc.outfitters_id) 
WHERE oc.categories_id IN (23, 26) 
GROUP BY o.id 
HAVING COUNT(DISTINCT oc.categories_id) >= 2

mysql组合搜索字段

2 个答案:

See Demo