Question

我想替换字符串中出现的小写字母后跟一个句点后跟一个大写字母（没有任何空格）来包含空格。

例如：

...inconvenient.The...

转换为

...inconvenient. The...

在Java中使用正则表达式的方法是什么？

Answer 1

我假设您要在小写和 dot 之后插入空格字符，如果后面跟着大写 ..

String s = "foo.Bar and bar.Baz but not FOO.BAR or BAR.baz";
s = s.replaceAll("(?<=[a-z]\\.)(?=[A-Z])", " ");
System.out.println(s); //=> "foo. Bar and bar. Baz but not FOO.BAR or BAR.baz"

说明：

(?<=            # look behind to see if there is:
 [a-z]          # any character of: 'a' to 'z'
 \.             # '.'
)               # end of look-behind
(?=             # look ahead to see if there is:
 [A-Z]          # any character of: 'A' to 'Z'
)               # end of look-ahead

Answer 2

像这样？ s/([a-z])\.([A-Z])/$1. $2/

Answer 3

就是这样：

result = subject.replace(/([a-z]\.)([A-Z])/g, "$1 $2");

解释正则表达式

(                        # group and capture to \1:
  [a-z]                  #   any character of: 'a' to 'z'
  \.                     #   '.'
)                        # end of \1
(                        # group and capture to \2:
  [A-Z]                  #   any character of: 'A' to 'Z'
)                        # end of \2

替换小写后跟句点后跟大写的正则表达式是什么？

3 个答案: